나는 아래에 공유하고있는 안드로이드 코드를 가지고 있습니다. 즉, 단계 9는 최종 단계에서 결과가 디스플레이되기 전에 입력 스트림이 json으로 변환 될 수있다. 그렇다면 어떻게? . 제발 내가 원하는 결과가 URL에서 얻을 수 있어야합니다. 나는 지금안드로이드에서 결과로 json을 얻으십시오
public class MainActivity extends Activity implements OnClickListener {
TextView tvIsConnected;
EditText etName,etCountry,etTwitter;
Button btnPost;
Person person;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
// get reference to the views
tvIsConnected = (TextView) findViewById(R.id.tvIsConnected);
etName = (EditText) findViewById(R.id.etName);
etCountry = (EditText) findViewById(R.id.etCountry);
//etTwitter = (EditText) findViewById(R.id.etTwitter);
btnPost = (Button) findViewById(R.id.btnPost);
// check if you are connected or not
if(isConnected()){
tvIsConnected.setBackgroundColor(0xFF00CC00);
tvIsConnected.setText("You are conncted");
}
else{
tvIsConnected.setText("You are NOT conncted");
}
// add click listener to Button "POST"
btnPost.setOnClickListener(this);
}
public static String POST(String url, Person person){
InputStream inputStream = null;
String result = "";
try {
// 1. create HttpClient
HttpClient httpclient = new DefaultHttpClient();
// 2. make POST request to the given URL
HttpPost httpPost = new HttpPost(url);
String json = "";
// 3. build jsonObject
JSONObject jsonObject = new JSONObject();
jsonObject.accumulate("Email", person.getName());
jsonObject.accumulate("pass", person.getCountry());
//jsonObject.accumulate("twitter", person.getTwitter());
// 4. convert JSONObject to JSON to String
json = jsonObject.toString();
// ** Alternative way to convert Person object to JSON string usin Jackson Lib
// ObjectMapper mapper = new ObjectMapper();
// json = mapper.writeValueAsString(person);
// 5. set json to StringEntity
StringEntity se = new StringEntity(json);
// 6. set httpPost Entity
httpPost.setEntity(se);
// 7. Set some headers to inform server about the type of the content
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");
// 8. Execute POST request to the given URL
HttpResponse httpResponse = httpclient.execute(httpPost);
// 9. receive response as inputStream
inputStream = httpResponse.getEntity().getContent();
// 10. convert inputstream to string
if(inputStream != null)
result = convertInputStreamToString(inputStream);
else
result = "Did not work!";
} catch (Exception e) {
Log.d("InputStream", e.getLocalizedMessage());
}
// 11. return result
return result;
}
public boolean isConnected(){
ConnectivityManager connMgr = (ConnectivityManager) getSystemService(Activity.CONNECTIVITY_SERVICE);
NetworkInfo networkInfo = connMgr.getActiveNetworkInfo();
if (networkInfo != null && networkInfo.isConnected())
return true;
else
return false;
}
@Override
public void onClick(View view) {
switch(view.getId()){
case R.id.btnPost:
if(!validate())
Toast.makeText(getBaseContext(), "Enter some data!", Toast.LENGTH_LONG).show();
// call AsynTask to perform network operation on separate thread
new HttpAsyncTask().execute("http://dev.myurl");
break;
}
}
private class HttpAsyncTask extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... urls) {
person = new Person();
person.setName(etName.getText().toString());
person.setCountry(etCountry.getText().toString());
//person.setTwitter(etTwitter.getText().toString());
return POST(urls[0],person);
}
// onPostExecute displays the results of the AsyncTask.
@Override
protected void onPostExecute(String result) {
Toast.makeText(getBaseContext(), result, Toast.LENGTH_LONG).show();
}
}
private boolean validate(){
if(etName.getText().toString().trim().equals(""))
return false;
else if(etCountry.getText().toString().trim().equals(""))
return false;
//else if(etTwitter.getText().toString().trim().equals(""))
//return false;
else
return true;
}
private static String convertInputStreamToString(InputStream inputStream) throws IOException{
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(inputStream));
String line = "";
String result = "";
while((line = bufferedReader.readLine()) != null)
result += line;
inputStream.close();
return result;
}
}
http://stackoverflow.com/questions/21480634/unable-to-loop-through-dynamic-json-string-recursively-in-android/까지를 XML로 결과를 얻고있다 21480997 # 21480997 – user2450263