이것을 실행 :에PHP의 Mcrypt 라이브러리 같은 후행 문자
var_dump(base64_encode(mcrypt_encrypt(MCRYPT_RIJNDAEL_256, '12345', '1abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyz', MCRYPT_MODE_ECB, mcrypt_create_iv(mcrypt_get_iv_size(MCRYPT_RIJNDAEL_256, MCRYPT_MODE_ECB), MCRYPT_RAND))));
var_dump(base64_encode(mcrypt_encrypt(MCRYPT_RIJNDAEL_256, '12345', '2abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyz', MCRYPT_MODE_ECB, mcrypt_create_iv(mcrypt_get_iv_size(MCRYPT_RIJNDAEL_256, MCRYPT_MODE_ECB), MCRYPT_RAND))));
var_dump(base64_encode(mcrypt_encrypt(MCRYPT_RIJNDAEL_256, '12345', '3abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyz', MCRYPT_MODE_ECB, mcrypt_create_iv(mcrypt_get_iv_size(MCRYPT_RIJNDAEL_256, MCRYPT_MODE_ECB), MCRYPT_RAND))));
var_dump(base64_encode(mcrypt_encrypt(MCRYPT_RIJNDAEL_256, '12345', '4abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyz', MCRYPT_MODE_ECB, mcrypt_create_iv(mcrypt_get_iv_size(MCRYPT_RIJNDAEL_256, MCRYPT_MODE_ECB), MCRYPT_RAND))));
var_dump(base64_encode(mcrypt_encrypt(MCRYPT_RIJNDAEL_256, '12345', '5abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyz', MCRYPT_MODE_ECB, mcrypt_create_iv(mcrypt_get_iv_size(MCRYPT_RIJNDAEL_256, MCRYPT_MODE_ECB), MCRYPT_RAND))));
그 결과 :
string 'X9VFmBzVWwUSoKPtE0VoEYxGkAPwVkUDQfQwF0wPDAVxedrGWE4oMCPBAF7FRBMoQsSUFwHhpknj/fHQqgQVPw==' (length=88)
string 'T/yn6lkyB73cEs57K2pUVNhFk2tDX02CbnBIU2c2I2VxedrGWE4oMCPBAF7FRBMoQsSUFwHhpknj/fHQqgQVPw==' (length=88)
string 'WysJWSV2k5gyYoQ4+hF0Uh2JqMJ6pTC8lcrgs1jmSklxedrGWE4oMCPBAF7FRBMoQsSUFwHhpknj/fHQqgQVPw==' (length=88)
string 'fMsJByfrZBYoQIgL/g+3i6jOPiaHh2Jf0vV59g1w1ZVxedrGWE4oMCPBAF7FRBMoQsSUFwHhpknj/fHQqgQVPw==' (length=88)
string 'Mw0AlrcC5v3v6swEg+wT+uTHf8MNrxdprD9GCpOe/45xedrGWE4oMCPBAF7FRBMoQsSUFwHhpknj/fHQqgQVPw==' (length=88)
공지 방법 문자열 같은 문자 세트의 모든 끝?
이 문제가 발생합니까?
데이터가 다르기 때문에 매번 새로운 초기화 벡터를 만들 때 완전히 다른 결과가 나올 것이라고 생각했을 것입니다.
데이터의 변화가 작을 때 완전히 다른 출력을 생성하는 또 다른 좋은 알고리즘이 있습니까?
http://codepad.viper-7.com/jVqpUU
http://codepad.viper-7.com/zD8ogl –