로그인 후 빈 Facebook 팝업

Question

처음 사용자가 앱에 액세스하면 모든 것이 정상적으로 작동합니다. 사용자는 내 앱을 인증하는 질문을 가진 팝업을 얻습니다. 그런 다음 다음 세션 (예 : 새로 고침)에서 즉시 팝업을 닫는 빈 팝업이 표시됩니다.

필자는 페이스 북이 새로운 액세스 토큰을 요구한다고 생각하지만 문제는 사용자 친화적이지 않다는 것입니다. 팝업이 열리고 닫힐 때 사용자는 뭔가 잘못되었거나 뭔가를 놓친다 고 생각합니다.

window.fbAsyncInit = function() { 
    FB.init({ 

    appId  : '', // App ID 
    channelUrl : '', // Channel File 
    status  : true, // check login status 
    cookie  : true, // enable cookies to allow the server to access the session 
    xfbml  : true // parse XFBML 
    }); 

    // Here we subscribe to the auth.authResponseChange JavaScript event. This event is fired 
    // for any authentication related change, such as login, logout or session refresh. This means that 
    // whenever someone who was previously logged out tries to log in again, the correct case below 
    // will be handled. 

    FB.Event.subscribe('auth.authResponseChange', function(response) { 
    // Here we specify what we do with the response anytime this event occurs. 
    if (response.status === 'connected') { 
     // The response object is returned with a status field that lets the app know the current 
     // login status of the person. In this case, we're handling the situation where they 
     // have logged in to the app. 

     if(accessToken) 
     { 
     //console.log("Connected WITH accesToken"); 
     testAPI(); 

     } 
     else{ 
      // console.log("Connected WITHOUTaccesToken"); 
    FB.login(function(response) { 
      // handle the response 
      uid = response.authResponse.userID; 
    accessToken = response.authResponse.accessToken; 
    //console.log(uid); 
    //console.log(accessToken); 
     }, {scope: 'friends_location, user_location, user_relationships'}); 

    } 


    } else if (response.status === 'not_authorized') { 
     // In this case, the person is logged into Facebook, but not into the app, so we call 
     // FB.login() to prompt them to do so. 
     // In real-life usage, you wouldn't want to immediately prompt someone to login 
     // like this, for two reasons: 
     // (1) JavaScript created popup windows are blocked by most browsers unless they 
     // result from direct interaction from people using the app (such as a mouse click) 
     // (2) it is a bad experience to be continually prompted to login upon page load. 

    //alert("You're logged in on FB but not on the APP"); 
     FB.login(); 

    } else { 
     // In this case, the person is not logged into Facebook, so we call the login() 
     // function to prompt them to do so. Note that at this stage there is no indication 
     // of whether they are logged into the app. If they aren't then they'll see the Login 
     // dialog right after they log in to Facebook. 
     // The same caveats as above apply to the FB.login() call here. 

// FB.login(); 
     //alert("You're offline on FB"); 
      FB.login(); 
    } 
    }); 




    }; 

    // Load the SDK asynchronously 

    (function(d){ 
    var js, id = 'facebook-jssdk', ref = d.getElementsByTagName('script')[0]; 
    if (d.getElementById(id)) {return;} 
    js = d.createElement('script'); js.id = id; js.async = true; 
    js.src = "//connect.facebook.net/en_US/all.js"; 
    ref.parentNode.insertBefore(js, ref); 
    }(document)); 


    // Here we run a very simple test of the Graph API after login is successful. 
    // This testAPI() function is only called in those cases. 
    function testAPI() { 

    FB.api('/'+uid+'/friends?fields=name,location,picture&accesstoken='+accessToken, function(response) { 

    } 


     //<img border="0" src="console.log(response.data[0].picture.data.url)"> 
     } 

    }); 

    } 

    //Logout 
    function fbLogout() { 
     //FB.init(); 
     FB.logout(function (response) { 
      //Do what ever you want here when logged out like reloading the page 
      //window.location.reload(); 
     }); 
    } 

가 어떻게이 빈 팝업을 방지 할 수 있습니다 : 여기

코드인가?

Answer 1

FB.login, 즉 FB.getLoginStatus을 명시 적으로 호출합니다.이 대화 상자는 로그인 대화 상자의 래퍼입니다. 이런 이유로 당신은 항상 팝업을 얻는다.

대신 getLoginStatus를 먼저 호출하고 실패 할 경우에만 login을 트리거하는 버튼을 제시하십시오.