MySQL 개수로 선택 + 값의 합

Question

다음 쿼리 (Wordpress DB)가 있습니다. 계산에 의해 응답 나는 또한 대부분이 코멘트를 감안하고 싶은, 그러나

$comment_query = $wpdb->get_results(" 
SELECT wp_comments.*, wp_comment_rating.*, (wp_comment_rating.ck_rating_up+wp_comment_rating.ck_rating_down) AS pop_comment 
FROM wp_comments, wp_comment_rating 
WHERE wp_comments.comment_post_ID = $post->ID 
AND wp_comments.comment_ID = wp_comment_rating.ck_comment_id 
AND wp_comments.comment_approved = 1 
ORDER BY pop_comment 
DESC 
LIMIT 1"); 

:

이것은 가장 "최대"결합 "아래로"평가 한 의견에 대한 데이터를 반환합니다 코멘트 당 매치 된 "comment_parent"의 수를 더한 다음, 그 합계를 내가 주문하는 "pop_comment"값에 더합니다.

본질적으로 가장 많이 결합 된 답글과 업/다운 등급을 가진 댓글에 대한 데이터를 얻고 싶습니다.

이

Answer 1

당신은 comment_parent

$comment_query = $wpdb->get_results(" 
SELECT wp_comments.*, wp_comment_rating.*, (wp_comment_rating.ck_rating_up+wp_comment_rating.ck_rating_down + (
    select count(*) from wp_comments c2 where c2.comment_parent=wp_comments.comment_ID 
    )) AS pop_comment 
FROM wp_comments, wp_comment_rating 
WHERE wp_comments.comment_post_ID = $post->ID 
AND wp_comments.comment_ID = wp_comment_rating.ck_comment_id 
AND wp_comments.comment_approved = 1 
ORDER BY pop_comment 
DESC 
LIMIT 1"); 

Answer 2

하여 수를 얻기 위해 하위 쿼리 수있는이에 대한 전체 의견을 얻기 위해 기본적으로는 단지 서브 쿼리를

를 작동해야 의미가 있습니다

희망 ... comment_parent 다음 필드에 SubQ/SubCount로 조인하십시오.

comment_query = $wpdb->get_results(" 
SELECT wp_comments.*, wp_comment_rating.*, (SubCount + pop_comment) AS total_rank, (wp_comment_rating.ck_rating_up+wp_comment_rating.ck_rating_down) AS pop_comment 
JOIN (SELECT COUNT(*) as SubCount, comment_parent as Sub_ID FROM wp_comments GROUP BY comment_parent) as SubQ 
ON wp_comments.comment_ID = SubQ.Sub_ID 
FROM wp_comments, wp_comment_rating 
WHERE wp_comments.comment_post_ID = $post->ID 
AND wp_comments.comment_ID = wp_comment_rating.ck_comment_id 
AND wp_comments.comment_approved = 1 ORDER BY total_rank DESC LIMIT 1");