주말, 휴일없이 두 날짜 사이의 공휴일 계산

Question

다음 두 날짜 사이의 주말 및 공휴일 수를 계산해야합니다.

var startDate = new Date("01/02/2014"); 
     var endDate = new Date("02/06/2014"); 
     var holidays = [new Date("01/06/2014"), new Date("01/26/2014")]; 

Answer 1

// Count days between the 2 dates 
var days = Math.floor(((Date.UTC(endDate.getFullYear(), endDate.getMonth(), endDate.getDate()) 
    - Date.UTC(startDate.getFullYear(), startDate.getMonth(), startDate.getDate()))/(24 * 60 * 60 * 1000))); 

// Count holidays 
var countHolidays = 0; 
for (var i = 0, len = holidays.length; i < len; ++i) 
    if (holidays[i] >= startDate && holidays[i] <= endDate) 
    ++countHolidays; 

// Vars used to count sundays and saturdays 
var adjustingDays1 = (7 - startDate.getDay()) % 7, // days between week of startDate and sunday 
    adjustingDays2 = (7 + 6 - startDate.getDay()) % 7, // days between week of startDate and saturday 
    oddDays = days % 7; // remainder of total days after dividing 7 
    completeWeeks = Math.floor(days/7); 

// Count weekend days 
var countWeekEndDays = completeWeeks + (oddDays >= adjustingDays1 ? 1 : 0) + 
      completeWeeks + (oddDays >= adjustingDays2 ? 1 : 0); 

console.log('holidays: ' + countHolidays); 
console.log('weekend days: ' + countWeekEndDays); 

Answer 2

이 부분 주를 순환하므로 최대 6 반복이 있습니다. 나는 순수한 JS로 그것을 해결하는보다 우아한 방법을 생각할 수 없다.

var startDate = new Date("01/02/2014"); 
var endDate = new Date("02/06/2014"); 

var diff = Math.abs(startDate - endDate); // in milliseconds 
var ms_per_day = 1000*60*60*24; 
var days = diff/ms_per_day + 1; // convert to days and add 1 for inclusive date range 
var mod = days % 7; 
var full_weeks = (days - mod)/7; 

var weekend_days = full_weeks * 2; 

if (mod != 0) { // iterate through remainder days 
    var startPartialWeek = new Date(); 
    var endPartialWeek = endDate; 
    startPartialWeek.setTime(endDate.getTime() - (mod - 1)*ms_per_day); 
    for (var d = startPartialWeek; d <= endPartialWeek; d.setDate(d.getDate() + 1)) { 
     if(d.getDay() == 0 || d.getDay() == 6) { 
      weekend_days++; 
     } 
    } 
} 

alert(weekend_days); 

이 수치는 토요일과 일요일을 의미하며 휴일은 아닙니다. 나는 다른 출처에서 얻은 휴일 날짜 모음을 반복하지 않고도 휴일을 할 수 있다고 생각하지 않습니다.

Answer 3

갖는 다음과 같은 두 가지 기능 :

var startDate = new Date("01/02/2014"); 
var endDate = new Date("02/06/2014"); 
var totalDays = calculateTotalDays(startDate, endDate); 
var weekendDays = totalDays - calcBusinessDays(startDate, endDate); 

을 그리고 시작과 endDate가 중간에 휴일을 계산 :

function calculateTotalDays(firstDate, secondDate){ 
    var oneDay = 24*60*60*1000; // hours*minutes*seconds*milliseconds 
    var firstDate = new Date(2008,01,12); 
    var secondDate = new Date(2008,01,22); 

    var diffDays = Math.round(Math.abs((firstDate.getTime() - secondDate.getTime())/(oneDay))); 
    return diffDays; 
} 

function calcBusinessDays(dDate1, dDate2) { // input given as Date objects 
    var iWeeks, iDateDiff, iAdjust = 0; 
    if (dDate2 < dDate1) return -1; // error code if dates transposed 
    var iWeekday1 = dDate1.getDay(); // day of week 
    var iWeekday2 = dDate2.getDay(); 
    iWeekday1 = (iWeekday1 == 0) ? 7 : iWeekday1; // change Sunday from 0 to 7 
    iWeekday2 = (iWeekday2 == 0) ? 7 : iWeekday2; 
    if ((iWeekday1 > 5) && (iWeekday2 > 5)) iAdjust = 1; // adjustment if both days on weekend 
    iWeekday1 = (iWeekday1 > 5) ? 5 : iWeekday1; // only count weekdays 
    iWeekday2 = (iWeekday2 > 5) ? 5 : iWeekday2; 

    // calculate differnece in weeks (1000mS * 60sec * 60min * 24hrs * 7 days = 604800000) 
    iWeeks = Math.floor((dDate2.getTime() - dDate1.getTime())/604800000) 

    if (iWeekday1 <= iWeekday2) { 
     iDateDiff = (iWeeks * 5) + (iWeekday2 - iWeekday1) 
    } else { 
     iDateDiff = ((iWeeks + 1) * 5) - (iWeekday1 - iWeekday2) 
    } 

    iDateDiff -= iAdjust // take into account both days on weekend 

    return (iDateDiff + 1); // add 1 because dates are inclusive 
} 

당신은 다음과 같이 총 weekenddays을 계산할 수 있습니다

var totalHolidays = 0; 
for (var i = 0, i < holidays.length; i++){ 
    var d = holidays[i].getDay();//Make sure holiday is not a weekendday! 
    if (holidays[i] >= startDate && holidays[i] <= endDate && !(d == 0 || d==6)) 
    totalHolidays++; 
}