2010-11-20 3 views
5

SQLAlchemy의 선언적 ORM을 사용하여 일대 다 관계를 정의하는 방법을 알아 내려고 the example을 작동 시키려고하지만 오류가 발생합니다. 내 하위 클래스 (이 나중에 선언 있기 때문에 ... 당연히) 발견SQLAlchemy 선언적 일대 다 정의되지 않은 오류

InvalidRequestError: When initializing mapper Mapper|Parent|parent, expression 'Child' failed to locate a name ("name 'Child' is not defined"). If this is a class name, consider adding this relationship() to the class after both dependent classes have been defined.

하지만 어떻게 오류없이, 나는이를 정의 할 수 없습니다?

코드 : 여기

from sqlalchemy import create_engine 
from sqlalchemy import Column, Integer, ForeignKey 
from sqlalchemy.ext.declarative import declarative_base 
from sqlalchemy.orm import sessionmaker, relationship 
from dev.historyMeta import VersionedMeta, VersionedListener 

global engine, Base, Session 
engine = create_engine('mysql+mysqldb://user:[email protected]:3306/testdb', pool_recycle=3600) 
Base = declarative_base(bind=engine, metaclass=VersionedMeta) 
Session = sessionmaker(extension=VersionedListener()) 


class Parent(Base): 
    __tablename__ = 'parent' 
    id = Column(Integer, primary_key=True) 
    children = relationship("Child", backref="parent") 

class Child(Base): 
    __tablename__ = 'child' 
    id = Column(Integer, primary_key=True) 
    parent_id = Column(Integer, ForeignKey('parent.id')) 

Base.metadata.create_all() 

답변

13

이다 나는 그것을 할 방법 :

from sqlalchemy import create_engine 
from sqlalchemy import Column, Integer, ForeignKey 
from sqlalchemy.ext.declarative import declarative_base 
from sqlalchemy.orm import sessionmaker, relationship 

engine = create_engine('sqlite://', echo=True) 
Base = declarative_base(bind=engine) 
Session = sessionmaker(bind=engine) 


class Parent(Base): 
    __tablename__ = 'parent' 
    id = Column(Integer, primary_key=True) 

class Child(Base): 
    __tablename__ = 'child' 
    id = Column(Integer, primary_key=True) 
    parent_id = Column(Integer, ForeignKey('parent.id')) 
    parent = relationship(Parent, backref='children') 

Base.metadata.create_all()