MYSQL JOIN 하나가있는 두 개의 열 및 데이터 가져 오기

Question

고정됨! 두 colums이

$result = $link->query('SELECT Software.*, 
Genre.Naam AS Genre, 
Console.Naam AS ConsoleNaam, 
Draager.Naam AS MediumNaam, 
Studio.Naam AS StudioNaam, 
Publisher.Naam AS PublisherNaam 
FROM Software 
INNER JOIN Genre ON Genre.Genre_ID = Software.Genre_ID 
INNER JOIN Console ON Console.Console_ID = Software.Console_ID 
INNER JOIN Draager ON Draager.Draager_ID = Software.Medium_ID 
INNER JOIN Company AS Studio ON Software.Studio_ID = Studio.Company_ID 
INNER JOIN Company AS Publisher ON Software.Publisher_ID = Publisher.Company_ID 
'); 

테이블 회사의 이름을 얻을 수있을 ID의 표 소프트웨어와 결합하는 PHP에서 MySQL의 하나와 결합려고 P

메신저 : anyones에 시간을 낭비 죄송합니다 그 회사.

위의 스크립트로 변경해야하는 내용에 대한 팁을 으로 보내주십시오.

Answer 1

그냥 대답해야하는 : D

$result = $link->query('SELECT Software.*, 
Genre.Naam AS Genre, 
Console.Naam AS ConsoleNaam, 
Draager.Naam AS MediumNaam, 
Studio.Naam AS StudioNaam, 
Publisher.Naam AS PublisherNaam 
FROM Software 
INNER JOIN Genre ON Genre.Genre_ID = Software.Genre_ID 
INNER JOIN Console ON Console.Console_ID = Software.Console_ID 
INNER JOIN Draager ON Draager.Draager_ID = Software.Medium_ID 
INNER JOIN Company AS Studio ON Software.Studio_ID = Studio.Company_ID 
INNER JOIN Company AS Publisher ON Software.Publisher_ID = Publisher.Company_ID 
'); 

Answer 2

오타가 있습니다. JOIN 맞춤법이 틀린 JION 등 :

$result = $link->query('SELECT Software.*, 
Genre.Naam AS Genre, 
Console.Naam AS ConsoleNaam, 
Draager.Naam AS MediumNaam, 
Studio.Naam AS StudioNaam, 
Publisher.Naam AS PublisherNaam 
FROM Software 
INNER JOIN Genre ON Genre.Genre_ID = Software.Genre_ID 
INNER JOIN Console ON Console.Console_ID = Software.Console_ID 
INNER JOIN Draager ON Draager.Draager_ID = Software.Medium_ID 
/* Misspelled JOIN below *(/ 
INNER JOIN Company AS Studio ON Software.Studio_ID = Studio.Company_ID 
INNER JOIN Company AS Publisher ON Software.Publisher_ID = Publisher.Company_ID 
');