최대 절전 모드 tx.commit()의 사용시 던져 예외를 삭제합니다.

Question

매우 단순한 하나의 ID만으로 POJO를 사용할 수 있으며 저장 및 업데이트가 정상적으로 작동하는 레코드를 삭제할 때 예외가 발생합니다. 만약 내가 commit()을 사용하지 않는다면 예외를주지는 않지만 만약 내가 그것을 사용한다면.! 난 tx.commit도 동일한 예외뿐만 아니라 경우 (wasCommitted()) 문을 사용할 경우 발생 여기 ... 위의 코드에서

public class DeleteCompanyRecords { 
public static boolean deleteCompany(String comname){ 
    Boolean res=false; 
    Session session = null; 
    String comid=GenCompanyCodeWhenGivenCompanyName.genCompanyCode(comname); 
    System.out.println(comid); 
    Transaction tx = null; 
    try{ 
     session = SessionCreate.getSessionFactory().openSession(); 
     tx=(Transaction) session.getTransaction(); 
     ElitSysCompanyMaster employee = 
       (ElitSysCompanyMaster)session.get(ElitSysCompanyMaster.class, comid); 
     session.delete(employee);res=true; 
     session.flush();//tx.commit() also gives exception here. 
    }catch (Exception e) { 
     session.getTransaction().rollback(); 
     e.printStackTrace(); 
     res=false; 

    } finally { 
     if (session != null) 
      if (session.isOpen()){ 
       session.close();} 
    } 
    return res; 
} 

코드이다. 안내해주십시오. 나는이 완전한 프로젝트를 위해 일하는 유일한 사람이다. 아무도 없습니다.

테이블은 매우 단순한 테이블이며 현재로서는 매핑이 없습니다. 예외는 그대로입니다.

SEVERE: Servlet.service() for servlet [jsp] in context with path [/SecurePass] threw exception [org.hibernate.TransactionException: Transaction not successfully started] with root cause 
org.hibernate.TransactionException: Transaction not successfully started 
    at org.hibernate.engine.transaction.spi.AbstractTransactionImpl.rollback(AbstractTransactionImpl.java:202) 
    at classes.deleteclasses.DeleteCompanyRecords.deleteCompany(DeleteCompanyRecords.java:25) 
    at org.apache.jsp.DeleteRecords.DeleteCompany_jsp._jspService(DeleteCompany_jsp.java:81) 
    at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) 
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:727) 
    at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432) 
    at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390) 
    at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334) 
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:727) 
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:303) 
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:208) 
    at org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52) 
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:241) 
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:208) 
    at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:220) 
    at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:122) 
    at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:501) 
    at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:171) 
    at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) 
    at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:950) 
    at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:116) 
    at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:408) 
    at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1040) 
    at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:607) 
    at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:316) 
    at java.util.concurrent.ThreadPoolExecutor.runWorker(Unknown Source) 
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(Unknown Source) 
    at org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61) 
    at java.lang.Thread.run(Unknown Source) 

Answer 1

당신은 트랜잭션, 그래서 session.getTransaction().begin()을 begin()해야합니다.

참고 : 인용문의 예외는 commit() 또는 flush()에는 있지만 catch 블록의 rollback()에는 발생하지 않습니다. stacktrace에서이를 볼 수 있습니다.