하나의 숫자 값이 잘못된 위치에 있지만 html 테이블의 위치를 평소에 수정할 수없는 html 테이블의 순서를 변경하려고합니다.개별적으로 행에서 jQuery 함수 실행
나는이 스크립트를 실행하여 td를 다시 주문하려고하지만 크기가 다시 주문되는 문제가 발생하지만 두 행 모두 하나에 복제하는 중이다 예 : 크기 조정은 8, 8,10,10,12,12 등
나는 행운을 비네팅으로 각기 다른 루프를 실행 해 보았습니다. 아무도 내게 힌트를 줄 수 없을까요? 다음은
는 테이블 형식이며 그것은 꺼낸 각 루프 나를 위해 작동하지 않는 것처럼 .. 내가 시도하고 다시 순서에 사용했던 코드입니다 아래<div id="attributeInputs" class="attribute-inputs js-type-grid">
<table class="js-grid">
<thead>
<tr>
<th class="js-col1"></th>
<th class="js-col2" colspan="8"></th>
</tr>
</thead>
<tbody><tr><th rowspan="1"></th>
<th class="js-rowtitleX">10</th>
<th class="js-rowtitleX">12</th>
<th class="js-rowtitleX">14</th>
<th class="js-rowtitleX">16</th>
<th class="js-rowtitleX">18</th>
<th class="js-rowtitleX">20</th>
<th class="js-rowtitleX">22</th>
<th class="js-rowtitleX">8</th>
</tr>
<tr>
<th class="js-rowtitleY">Red</th>
<td class="js-gridBlock js-In_stock" data-attvalue1="10" data-attvalue2="Red" <span class="status">In stock</span></td>
<td class="js-gridBlock js-In_stock" data-attvalue1="12" data-attvalue2="Red" <span class="status">In stock</span></td>
<td class="js-gridBlock js-In_stock" data-attvalue1="14" data-attvalue2="Red" <span class="status">In stock</span></td>
<td class="js-gridBlock js-In_stock" data-attvalue1="16" data-attvalue2="Red" <span class="status">In stock</span></td>
<td class="js-gridBlock js-In_stock" data-attvalue1="18" data-attvalue2="Red" <span class="status">In stock</span></td>
<td class="js-gridBlock js-In_stock" data-attvalue1="20" data-attvalue2="Red" <span class="status">In stock</span></td>
<td class="js-gridBlock js-In_stock" data-attvalue1="22" data-attvalue2="Red" <span class="status">In stock</span></td>
<td class="js-gridBlock js-In_stock" data-attvalue1="8" data-attvalue2="Red" <span class="status">In stock</span></td>
</tr>
<tr>
<th class="js-rowtitleY">Blue</th>
<td class="js-gridBlock js-In_stock" data-attvalue1="10" data-attvalue2="Blue" <span class="status">In stock</span></td>
<td class="js-gridBlock js-In_stock" data-attvalue1="12" data-attvalue2="Blue" <span class="status">In stock</span></td>
<td class="js-gridBlock js-In_stock" data-attvalue1="14" data-attvalue2="Blue" <span class="status">In stock</span></td>
<td class="js-gridBlock js-In_stock" data-attvalue1="16" data-attvalue2="Blue" <span class="status">In stock</span></td>
<td class="js-gridBlock js-In_stock" data-attvalue1="18" data-attvalue2="Blue" <span class="status">In stock</span></td>
<td class="js-gridBlock js-In_stock" data-attvalue1="20" data-attvalue2="Blue" <span class="status">In stock</span></td>
<td class="js-gridBlock js-In_stock" data-attvalue1="22" data-attvalue2="Blue" <span class="status">In stock</span></td>
<td class="js-gridBlock js-In_stock" data-attvalue1="8" data-attvalue2="Blue" <span class="status">In stock</span></td>
</tr>
</tbody
</table>
</div>
$("#attributeInputs > table > tbody > tr > td").sort(sort_td).appendTo('#attributeInputs > table > tbody > tr:nth-child(n+2)');
function sort_td(a, b){
return ($(b).data('attvalue1')) < ($(a).data('attvalue1')) ? 1 : -1;}
는 다음 배열을 정렬하고 다시 추가 할 해당 배열을 루프, .each 사용하여'th' 요소를 통해보고()와 배열에 값을 저장하려고 했습니까? – AdamMcquiff