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서버에서 JSONObject로 데이터를 가져와 내 테이블에 저장하고 있습니다.Android : Sqlite 오류 - (1) "null"근처 : 구문 오류
다음 오류가 발생했습니다.
11-22 02 : 18 : 35.489 : E/AndroidRuntime (2597) android.database.sqlite.SQLiteException : 근처 "NULL"구문 오류 (코드 1)의 컴파일 동안, 표를 작성 Conntact (null INTEGER PRIMARY KEY AUTOINCREMENT, null TEXT, null TEXT, null TEXT, null TEXT, null TEXT, null TEXT);
for(int i=0;i<contactdata.length();i++)
{
JSONObject cont = contactdata.getJSONObject(i);
String con_id = getValue(cont, "id");
System.out.println("contactid"+con_id);
String first_name = getValue(cont, "first_name");
String last_name = getValue(cont, "last_name");
String short_name = getValue(cont, "short_name");
String pid = getValue(cont, "pid");
String cid = getValue(cont, "cid");
String number = getValue(cont, "914424411295");
Conntact con = new Conntact(getActivity());
con.insertValues(con_id, short_name, first_name, last_name, number, pid, cid);
Toast.makeText(ctx, "contact inside", Toast.LENGTH_SHORT).show();
}
이 내 Conntact 클래스입니다
public class Conntact {
public Conntact() {
// TODO Auto-generated constructor stub
}
static SQLiteDatabase db;
static ContactDB dedb;
public Conntact(Context context)
{
dedb = new ContactDB(context);
}
public static SQLiteDatabase open()
{
return dedb.getWritableDatabase();
}
public void close()
{
dedb.close();
}
public void insertValues(String con_id, String short_name,String first_name,String last_name,String pid,String cid,String number)
{
db = open();
ContentValues values = new ContentValues();
values.put(ContactDB.con_id, con_id);
values.put(ContactDB.short_name, short_name);
values.put(ContactDB.first_name, first_name);
values.put(ContactDB.last_name, last_name);
values.put(ContactDB.pid, pid);
values.put(ContactDB.cid, cid);
values.put(ContactDB.number, number);
db.insert(ContactDB.TABLE_NAME, null, values);
this.close();
}
public ArrayList<String> getValues()
{
ArrayList<String> names = new ArrayList<String>();
db = open();
String query = "select * from "+ContactDB.TABLE_NAME;
Cursor cursor = db.rawQuery(query, null);
if(cursor.moveToFirst())
{
do{
names.add(cursor.getString(cursor.getColumnIndex(ContactDB.con_id)));
names.add(cursor.getString(cursor.getColumnIndex(ContactDB.number)));
names.add(cursor.getString(cursor.getColumnIndex(ContactDB.first_name)));
names.add(cursor.getString(cursor.getColumnIndex(ContactDB.last_name)));
names.add(cursor.getString(cursor.getColumnIndex(ContactDB.short_name)));;
names.add(cursor.getString(cursor.getColumnIndex(ContactDB.pid)));;
//names.add(cursor.get)
}while(cursor.moveToNext());
}
return names;
}
public static boolean isAvailable(String number)
{
db = open();
String query = "select * from"+ContactDB.TABLE_NAME+"where"+ContactDB.number+"="+number;
Cursor c =db.rawQuery(query, null);
if(c==null)
{
return false;
}else
return true;
}
}
이 내 ContactDB 클래스
내가 실수를 한 곳 모르겠어요public class ContactDB extends SQLiteOpenHelper{
public static final String DATABASE_NAME = "AA_DB_NAME";
public static final String TABLE_NAME = "Conntact";
public static final int VERSION = 1;
public ContactDB(Context context) {
super(context, DATABASE_NAME, null, VERSION);
// TODO Auto-generated constructor stub
}
public static String con_id;
public static String short_name;
public static String first_name;
public static String last_name;
public static String pid;
public static String cid;
public static String number;
public static String CREATE_QUERY = "create table "+TABLE_NAME+" ("+con_id+" INTEGER PRIMARY KEY AUTOINCREMENT, "+short_name+" TEXT, "+first_name+" TEXT, "+last_name+" TEXT, "+pid+" TEXT, "+cid+" TEXT, "+number+" TEXT);";
@Override
public void onCreate(SQLiteDatabase db) {
// TODO Auto-generated method stub
db.execSQL(CREATE_QUERY);
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
// TODO Auto-generated method stub
db.execSQL("DROP TABLE "+TABLE_NAME+" IF NOT EXISTS");
}
}
입니다. 내가 잘못 들어간다면 제발 도와주세요.
"ContactDB"클래스의'public static String'에 값을 할당해야합니다. 또한 '최종'으로 만들어야합니다. –