php에서 현재 로그인 한 사용자의 사용자 이름을 얻는 방법은 무엇입니까?

Question

설정, 프로필 및 로그 아웃 옵션이 포함 된 드롭 다운에 로그인 한 사용자의 사용자 이름을 표시하려고합니다. 여기 login.php

<?php 
session_start(); // Starting Session 
$error[] = ''; // Variable To Store Error Message 
require 'function/general.php'; 
require 'function/users.php'; 
include 'includes/db_connect.php'; 


if(empty($_POST)=== false){ 
$username = $_POST['username']; 

$password = $_POST['password']; 

if(empty($username) === true || empty($password) === true){ 
    $error[] = "you need to enter username and password"; 
} 
else if(user_exists($username)=== false){ 
    $error[] = "cant find username . have you registerd"; 
} 
else if (user_active($username)=== false) { 
    $error[] = "havent activated account"; 

}else{ 
    $login = login($username,$password); 
    if($login === false){ 
     $error[] = "invalide login credentials"; 
    } 
    else{ 
     $_SESSION['id'] = $login; 

     header("Location: index.php"); 
     exit(); 
    } 


} 


} 

?> 

여기

users.php 내가 로그인 한 사용자의 이름을 표시 할 위치

여기

<?php 

function logged_in(){ 
    return(isset($_SESSION['id'])) ? true : false; 

} 

function user_exists($username) { 
    $username = sanitize($username); 


    return (mysql_result(mysql_query("SELECT COUNT(`id`) FROM `login` WHERE `username` ='$username' "), 0) == 1) ? true : false; 

} 

function user_active($username) { 
    $username = sanitize($username); 


    return (mysql_result(mysql_query("SELECT COUNT(`id`) FROM `login` WHERE `username` ='$username' AND `active` = 1 "), 0) == 1) ? true : false; 

} 

function user_id_from_username($username){ 
    $username = sanitize ($username); 
    return mysql_result(mysql_query("SELECT `id` FROM `login` WHERE `username` = '$username'"),0, 'id'); 
} 

function login($username , $password){ 

    $id = user_id_from_username($username); 

    $username = sanitize($username); 
    $password = md5($password); 

    return (mysql_result(mysql_query("SELECT COUNT(`id`) FROM `login` WHERE `username` ='$username' AND `password` = '$password'") , 0) == 1) ? $id : false; 

} 

는 모든 기능이 포함되어 있습니다

<?php 
session_start(); 

include 'includes/bootstrap.html'; 


require 'function/general.php'; 
require 'function/users.php'; 
require 'includes/bootstrap.html'; 
?> 

<script> 
$('.dropdown-toggle').dropdown(); 

</script> 
<!---------navbar ---> 

<nav class="navbar navbar-default" role="navigation"> 
    <div class="container-fluid"> 
     <!-- Brand and toggle get grouped for better mobile display --> 
     <div class="navbar-header"> 
      <button type="button" class="navbar-toggle collapsed" data-toggle="collapse" data-target="#bs-example-navbar-collapse-1"> 
       <span class="sr-only">Toggle navigation</span> 
       <span class="icon-bar"></span> 
       <span class="icon-bar"></span> 
       <span class="icon-bar"></span> 
      </button> 
      <a class="navbar-brand" href="index.php"><h3>Utile</h3></a> 
     </div> 

     <!-- Collect the nav links, forms, and other content for toggling --> 
     <div class="collapse navbar-collapse" id="bs-example-navbar-collapse-1"> 
      <ul class="nav navbar-nav"> 
       <li><a href="index.php">Home <span class="sr-only">(current)</span></a></li> 
       <li><a href="#">Browse Photos</a></li> 

      </ul> 

      <?php if (logged_in() === true) { 
       ?> 
       <!-- <ul class="nav navbar-nav navbar-right"> 
         <li><a href="logout.php">Logout</a><a href="profile.php">Profile</a><a href="settings.php">Settings</a></li> 

       --> 
       <ul class="nav navbar-nav navbar-right"> 
        <li class="dropdown"> 
         <a href="#" class="dropdown-toggle" data-toggle="dropdown" role="button" aria-expanded="false"> **here i want username** <span class="caret"></span></a> 
         <ul class="dropdown-menu" role="menu"> 
          <li><a href="logout.php">Logout</a></li> 
          <li><a href="profile.php">Profile</a></li> 
          <li><a href="#">Setting</a></li> 
          <li class="divider"></li> 
          <li><a href="#">Separated link</a></li> 
          <li class="divider"></li> 
          <li><a href="#">One more separated link</a></li> 
         </ul> 
        </li> 

        <?php 
       } else { 
        ?> 

        <ul class="nav navbar-nav navbar-right"> 
         <li><a href="login.php">Login</a></li> 
         <li><a href="register.php">Sign Up</a></li> 
       <?php } ?> 

        <li><a href="registerpro.php"><button type="button" class="btn btn-primary">Become Professional</button></a></li> 

       </ul> 
     </div><!-- /.navbar-collapse --> 
    </div><!-- /.container-fluid --> 
</nav> 

Answer 1

하는 경우 phpacademy의 로그인 시스템을 따라 갔다면 다음 기능이 있어야합니다.

function user_data($user_id) { 
    $data = array(); 
    $user_id = (int)$user_id; 

    $func_num_args = func_num_args(); 
    $func_get_args = func_get_args(); 

    if ($func_num_args > 1) { 
     unset($func_get_args[0]); 

     $fields = '`' .implode('`, `', $func_get_args) . '`'; 
     $data = mysql_fetch_assoc(mysql_query("SELECT $fields FROM `users` WHERE `user_id` = $user_id")); 

     return $data; 
    } 
} 

function user_id_from_username($username) { 
    $username = sanitize($username); 
    return mysql_result(mysql_query("SELECT `user_id` FROM `users` WHERE `username` = '$username'"), 0, 'user_id'); 
} 

는 그런 다음 마우스 오른쪽 .. 내가 당신을 추측 할 수 ... 코드를 보면

$username= $user_data['username'];