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에 JSP (Eclipse)를 사용하여 데이터 삽입하기 그래서 JSP 형식의 레코드를 데이터베이스 (XAMPP, MySQL)에 등록 (삽입)하려고합니다. 세부 사항은 다음과 같습니다 : 나는 로컬 호스트에서 실행하고 세부 사항을 입력 할 때데이터베이스 (XAMPP, MySQL)
는 register.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<form action = "RegisterController" method = "post">
<input type = "text" name = "email" placeholder = "Your e-mail"><br><br>
<input type = "text" name = "firstname" placeholder = "First name"><br><br>
<input type = "text" name = "lastname" placeholder = "Last name"><br><br>
<input type = "text" name = "address" placeholder = "Home address"><br><br>
<input type = "text" name = "phone" placeholder = "Your phone number"><br><br>
<input type = "password" name = "password"><br><br>
<input type = "submit" name = "submit" value = "Register">
</form>
</body>
</html>
RegisterController.java
package cms.com;
import java.io.IOException;
import java.io.PrintWriter;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.SQLException;
import javax.servlet.ServletConfig;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class RegisterController
*/
public class RegisterController extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public RegisterController() {
super();
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
}
/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
try{
String email = request.getParameter("email");
String firstname = request.getParameter("firstname");
String lastname = request.getParameter("lastname");
String address = request.getParameter("address");
String phone = request.getParameter("phone");
String password = request.getParameter("password");
String sql = "insert into users(email,firstname,lastname,address,phone,password) values(?,?,?,?,?,?)";
Class.forName("com.mysql.jdbc.Driver");
Connection conn = DriverManager.getConnection("jdbc:mysql://localhost:3306/cms","root","");
PreparedStatement pst = conn.prepareStatement(sql);
pst.setString(1,email);
pst.setString(2,firstname);
pst.setString(3,lastname);
pst.setString(4,address);
pst.setString(5, phone);
pst.setString(6, password);
pst.executeUpdate();
PrintWriter out = response.getWriter();
out.println("You have successfully registered!");
}
catch(ClassNotFoundException e){
e.printStackTrace();
}
catch(SQLException e){
e.printStackTrace();
}
}
}
그래서, 그것은 단지 빈 페이지를 표시 테이블에 아무런 업데이트도 없었습니다. 디버깅을하면 런타임 중에 오류가 표시되지 않습니다. 동적 모듈 2.5와 Apache Tomcat 7.0에서 Eclipse Luna를 사용하고 있습니다.