첫 번째 봄 예제 코드를 실행했을 때이 오류가 발생했습니다. 봄처럼 보이지 않습니다org.springframework.beans.factory.NoSuchBeanDefinitionException
어떻게 든 콩을 재조정하지만 나는 이유를 모른다. 나는 bean 정의 파일을 만들고 거기에 하나의 bean을 추가했다.
그런 다음 해당 파일이 WEBINF 폴더에 있습니다. 어쨌든 이것은 아무 문제없이 작동해야하지만 외모는
입니다. 여기에 몇 가지 문제가 있습니다. 아래는 나의 bean 정의 파일과 JSP이다. 아무도 말해 줄 수 없다
내가 뭘 잘못하고 있니?
applicationContext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">
<bean id="HelloSpring" class="com.spring.toby.HelloSpring"></bean>
</beans>
HelloSpring.java
package com.spring.toby;
public class HelloSpring {
public String sayHello(String name){
return "Hello " + name;
}
}
HelloSpring.jsp
<%@ page language="java" contentType="text/html; charset=EUC-KR"
pageEncoding="EUC-KR"%>
<%@ page import="org.springframework.context.ApplicationContext" %>
<%@ page import="org.springframework.web.context.support.WebApplicationContextUtils" %>
<%@ page import="com.spring.toby.HelloSpring" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=EUC-KR">
<title>Insert title here</title>
</head>
<body>
<%
ApplicationContext context = WebApplicationContextUtils.getWebApplicationContext(
request.getSession().getServletContext());
out.println("check");
HelloSpring helloSpring = context.getBean(HelloSpring.class);
//out.println(helloSpring.sayHello("seho"));
%>
</body>
</html>
web.xml의
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee /web-app_2_5.xsd">
<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
,745 1,515,
여기 내 에러 로그
org.apache.jasper.JasperException이다 예외 라인 (17)
14 처리 JSP 페이지 /WEB-INF/views/hellospring.jsp를 발생 ApplicationContext의 컨텍스트 = WebApplicationContextUtils. getWebApplicationContext ( 15 : request.getSession(). getServletContext()); 16 : out.println ("check"); 17 : HelloSpring helloSpring = context.getBean (HelloSpring.class); 18 :
19 : //out.println(helloSpring.sayHello("seho "))); 20 %> 당신은는 contextConfigLocation에 applicationContext.xml
를 추가 할 필요가
Stacktrace:
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:568)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:470)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
org.springframework.web.servlet.view.InternalResourceView.renderMergedOutputModel(InternalResourceView.java:238)
org.springframework.web.servlet.view.AbstractView.render(AbstractView.java:262)
org.springframework.web.servlet.DispatcherServlet.render(DispatcherServlet.java:1157)
org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:927)
org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:827)
org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:882)
org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:778)
javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
root cause
org.springframework.beans.factory.NoSuchBeanDefinitionException: No unique bean of type [com.spring.toby.HelloSpring] is defined: expected single bean but found 0:
org.springframework.beans.factory.support.DefaultListableBeanFactory.getBean(DefaultListableBeanFactory.java:271)
org.springframework.context.support.AbstractApplicationContext.getBean(AbstractApplicationContext.java:1101)
org.apache.jsp.WEB_002dINF.views.hellospring_jsp._jspService(hellospring_jsp.java:81)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
org.springframework.web.servlet.view.InternalResourceView.renderMergedOutputModel(InternalResourceView.java:238)
org.springframework.web.servlet.view.AbstractView.render(AbstractView.java:262)
org.springframework.web.servlet.DispatcherServlet.render(DispatcherServlet.java:1157)
org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:927)
org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:827)
org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:882)
org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:778)
javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
올바른 컨텍스트 파일을 사용하고 있습니까? 'web.xml' pls의 내용을 게시하십시오. – vacuum
web.xml을 추가했습니다. 오 ... 이제 알았습니다 .. applicationContext.xml을 context-param에 포함 시키시겠습니까? –