파이썬에서 단어 조합하기 (순열?)

Question

4 단어가 있다고 가정합니다. 어떻게 이런 식으로 가입 할 수 있습니까?

"orangeapple/orangegrapes/orangepear/applegrapes/applepear/grapespear/orangeapplegrapes/orangeapplepear/applegrapespear" 

내가 생각하고 :

s = orange apple grapes pear 

결과는 문자열 될 것

list_words = s.split(' ') 
for l in list_words: 

그리고 열거 사용할 수 있습니까? 이것이 당신이이 기능을하기 위해 사용하는 것입니까?

Answer 1

아마도 이것이 원하는 것일까요? 결과 (선명도) 'ABC'를 실행하면

는

s = "orange apple grapes pear" 

from itertools import product 
l = s.split() 
r='/'.join(''.join(k*v for k,v in zip(l, x)) 
      for x in product(range(2), repeat=len(l)) 
      if sum(x) > 1) 
print r 

입니다 :

bc/ac/ab/abc 

(포스터에서 주석 이후에 업데이트되었습니다.)이 목록의 모든 부분 집합을 제공

Answer 2

s = 'orange apple grapes pear' 

list_words = s.split() 

num = len(list_words) 
ans = [] 
for i in xrange(1,2**num-1): 
    cur = [] 
    for j,word in enumerate(list_words): 
    if i & (1 << j): 
     cur.append(word) 
    if len(cur) > 1: 
    ans.append(''.join(cur)) 
print '/'.join(ans) 

빈 단어, 한 단어 및 모든 단어를 제외하고 귀하의 예를 들어 : orangeapple/orangegrapes/applegrapes/orangeapplegrapes/orangepear/applepear/orangeapplepear/grapespear/orangegrapespear/applegrapespear

Answer 3

>>> import itertools 
>>> from itertools import combinations 
>>> s = "orange apple grapes pear".split() 
>>> res=[] 
>>> for i in range(2,len(s)+1): 
...  res += [''.join(x) for x in combinations(s,i)] 
... 
>>> '/'.join(res) 
'orangeapple/orangegrapes/orangepear/applegrapes/applepear/grapespear/orangeapplegrapes/orangeapplepear/orangegrapespear/applegrapespear/orangeapplegrapespear' 

Answer 4

>>> s = "orange apple grapes pear".split() 
>>> '/'.join(''.join(k) for k in [[s[j] for j in range(len(s)) if 1<<j&i] for i in range(1<<len(s))] if len(k)>1) 
'orangeapple/orangegrapes/applegrapes/orangeapplegrapes/orangepear/applepear/orangeapplepear/grapespear/orangegrapespear/applegrapespear/orangeapplegrapespear' 

Answer 5

>>> from itertools import combinations 
>>> s = "orange apple grapes pear".split() 
>>> '/'.join([''.join(y) for y in [ x for z in range(len(s)) for x in combinations(s,z)] if len(y)>1]) 
'orangeapple/orangegrapes/orangepear/applegrapes/applepear/grapespear/orangeapplegrapes/orangeapplepear/orangegrapespear/applegrapespear'