mysql을 하나의 테이블

Question

에서 여러 카운트는 내가 하나 개의 쿼리에이 쿼리를 만들 수

SELECT 
    DATE_FORMAT(`member_subscribe_at`, '%d-%m-%y') Tanggal, 
    count(`member_msisdn`) 'total_reg' 
FROM 
    `t_push_member` 
WHERE 
    `service_keycode`='nocan' 
GROUP BY 
    Tanggal, 
    'total_reg' 
ORDER BY 
    Tanggal 

및

SELECT 
    DATE_FORMAT(`member_unsubscribe_at`, '%d-%m-%Y') Tanggal, 
    COUNT(`member_msisdn`) 'total_unreg' 
FROM 
    `t_push_member` 
WHERE 
    `service_keycode`='nocan' 
GROUP BY 
    Tanggal, 'total_unreg' 
ORDER BY 
    Tanggal 

방법 t_push_member 하나 개의 테이블에서이 쿼리가?

Answer 1

둘 사이에 사용 "노동 조합"- 대신에와

Answer 2

select * 
from 
(SELECT DATE_FORMAT(member_subscribe_at, '%d-%m-%y') Tanggal, count(member_msisdn),'REG' as Registered FROM t_push_member 
    where service_keycode='nocan' 
    group by Tanggal 

    UNION 

    SELECT DATE_FORMAT(member_unsubscribe_at, '%d-%m-%Y') Tanggal, count(member_msisdn),'NOT_REG' as Registered FROM t_push_member 
    where service_keycode='nocan' 
    group by Tanggal 
) 
order by Tanggal 

당신은 그것을 하나 개의 쿼리에서 수행하려면 하위 쿼리를 사용할 수 있습니다 http://www.w3schools.com/sql/sql_union.asp