-5
어떤 논리 오류가 발생했는지 묻고 싶습니다. 내가 CD 모든 유형의 숫자 1을 입력하더라도, 출력은 5 % 할인이있을 것이다 .. 5 % 할인C++ 다른 논리 오류 및 잘못된 출력
#include <iostream>
using namespace std;
int main() {
int type_i,type_l,type_o,type_c;
float cost_i,cost_l,cost_o,cost_c,discount_i,discount_l,discount_o,discount_c,discounted_i,discounted_l,discounted_o,discounted_c,total_dis,amount;
float price_i=39.9,price_l=29.9,price_o=49.9,price_c=59.9;
cout<<"\t\t\tPower House\n";
cout<<"Quantity of International CD:";
cin>>type_i;
cout<<"Quantity of Local CD:";
cin>>type_l;
cout<<"Quantity of Oldies CD:";
cin>>type_o;
cout<<"Quantity of Classic CD:";
cin>>type_c;
cost_i=type_i*price_i;
cost_l=type_l*price_l;
cost_o=type_o*price_o;
cost_c=type_c*price_c;
if (2<=type_i<=5){
discount_i=cost_i*0.05;
discounted_i=cost_i*0.95;
}
else if(6<=type_i<=10){
discount_i=cost_i*0.1;
discounted_i=cost_i*0.9;
}
else if(11<=type_i<=15){
discount_i=cost_i*0.15;
discounted_i=cost_i*0.85;
}
else if(16<=type_i<=20){
discount_i=cost_i*0.2;
discounted_i=cost_i*0.8;
}
else if(type_i>20){
discount_i=cost_i*0.25;
discounted_i=cost_i*0.75;
}
else if(0<=type_i<=1){
discounted_i=cost_i;
}
if (2<=type_l<=5){
discount_l=cost_l*0.05;
discounted_l=cost_l*0.95;
}
else if(6<=type_l<=10){
discount_l=cost_l*0.1;
discounted_l=cost_l*0.9;
}
else if(11<=type_l<=15){
discount_l=cost_l*0.15;
discounted_l=cost_l*0.85;
}
else if(16<=type_l<=20){
discount_l=cost_l*0.2;
discounted_l=cost_l*0.8;
}
else if(type_l>20){
discount_l=cost_l*0.25;
discounted_l=cost_l*0.75;
}
else if(0<=type_l<=1){
discounted_l=cost_l;
}
if (2<=type_o<=5){
discount_o=cost_o*0.05;
discounted_o=cost_o*0.95;
}
else if(6<=type_o<=10){
discount_o=cost_o*0.1;
discounted_o=cost_o*0.9;
}
else if(11<=type_o<=15){
discount_o=cost_o*0.15;
discounted_o=cost_o*0.85;
}
else if(16<=type_o<=20){
discount_o=cost_o*0.2;
discounted_o=cost_o*0.8;
}
else if(type_o>20){
discount_o=cost_o*0.25;
discounted_o=cost_o*0.75;
}
else if (0<=type_o<=1){
discounted_o=cost_o;
}
if (2<=type_c<=5){
discount_c=cost_c*0.05;
discounted_c=cost_c*0.95;
}
else if(6<=type_c<=10){
discount_c=cost_c*0.1;
discounted_c=cost_c*0.9;
}
else if(11<=type_c<=15){
discount_c=cost_c*0.15;
discounted_c=cost_c*0.85;
}
else if(16<=type_c<=20){
discount_c=cost_c*0.2;
discounted_c=cost_c*0.8;
}
else if(type_c>20){
discount_c=cost_c*0.25;
discounted_c=cost_c*0.75;
}
else if(0<=type_c<=1){
discounted_c=cost_c;
}
total_dis=discount_i+discount_l+discount_o+discount_c;
amount=discounted_i+discounted_l+discounted_o+discounted_c;
cout<<"Total discount:"<<total_dis;
cout<<"\nAmount due:"<<amount;
}
https://i.stack.imgur.com/qEPgK.png
이^위의 제 질문에만 CD의 2 ~ 5 구매입니다 이 프로그램의 경우
'2 <= type_i <= 5'는'(2 <= type_i) <= 5와 동일하기 때문에 항상 '참'입니다. '(참) <= 5'와 동일합니다 '사실'. – user463035818
두 조건 '2 <= type_i 및 type_i <= 5'를 확인해야합니다. – user463035818
질문 자체와 완전히 관련이 없습니다. 하지만 이런 문제가 생기면 나는 CD 클래스를 만들 것이다. – quantik