SELECT와 다른 결과 및 내부에서보기

Question

SELECT 문의 결과가 VIEW 내부 SELECT의 결과와 다릅니다. 문제를 수정하고 동일한 결과를보기에서 얻는 방법?

조치는 테이블 :

+--+---------+--------------+-----------+------+ 
|id|person_id|action_type_id|currency_id|sum | 
+--+---------+--------------+-----------+------+ 
|1 |1  |1    |1   | 1.00 | 
|2 |1  |1    |1   | 5.00 | 
|3 |1  |1    |2   |10.00 | 
|4 |1  |2    |1   | 2.00 | 
|5 |2  |1    |1   |20.00 | 
|6 |2  |2    |2   | 5.00 | 
+--+---------+--------------+-----------+------+ 

선택 :

SELECT person_id AS p, currency_id AS c, 
(
CAST(
COALESCE(
(SELECT SUM(sum) FROM actions WHERE action_type_id=1 AND person_id=p AND currency_id=c) 
, 0) 
AS DECIMAL(11,2)) - 
CAST(
COALESCE(
(SELECT SUM(sum) FROM actions WHERE action_type_id=2 AND person_id=p AND currency_id=c) 
, 0) 
AS DECIMAL(11,2)) 
) AS sum 
FROM actions 
GROUP BY currency_id, person_id 
ORDER BY person_id, currency_id; 

결과 :

CREATE VIEW p_sums AS 
SELECT person_id AS p, currency_id AS c, 
(
CAST(
COALESCE(
(SELECT SUM(sum) FROM actions WHERE action_type_id=1 AND person_id=p AND currency_id=c) 
, 0) 
AS DECIMAL(11,2)) - 
CAST(
COALESCE(
(SELECT SUM(sum) FROM actions WHERE action_type_id=2 AND person_id=p AND currency_id=c) 
, 0) 
AS DECIMAL(11,2)) 
) AS sum 
FROM actions 
GROUP BY currency_id, person_id 
ORDER BY person_id, currency_id; 

SELECT * FROM p_sums; 

,369 :

+--+--+------+ 
|p |c |sum | 
+--+--+------+ 
|1 |1 | 4.00 | 
|1 |2 |10.00 | 
|2 |1 |20.00 | 
|2 |2 |-5.00 | 
+--+--+------+ 

하는 내부보기를 선택

결과 :

+--+--+------+ 
|p |c |sum | 
+--+--+------+ 
|1 |1 |29.00 | 
|1 |2 |29.00 | 
|2 |1 |29.00 | 
|2 |2 |29.00 | 
+--+--+------+ 

Answer 1

당신이 할 수 없습니다 :

SELECT person_id AS p, currency_id AS c, SUM(CASE action_Type_id WHEN 1 THEN sum WHEN 2 THEN -sum END) as sum 
FROM actions 
GROUP BY currency_id, person_id 
ORDER BY person_id, currency_id; 

즉, 서브 쿼리를 없애고 하나의 합계를 작성하십시오 (action_type_id 2 값을 음수로 지정)