스프링 MVC 애플리케이션에서 스프링 보안 활성화

Question

스프링 애플 리케이션에서 스프링 보안 2.5를 사용하려고하는데 구성 문제가 발생했습니다. 나는 몇 가지 예를 따라하고 그들이하는 일을 해왔지만, 내가 설정 한 다른 것이 문제를 일으키는 것 같아요. 여기

내 web.xml에 있습니다 : 내 보안의 context.xml

<?xml version="1.0" encoding="UTF-8"?> 
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" 
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" 
id="WebApp_ID" version="2.5"> 
<display-name>onBoardingUI</display-name> 


<listener> 
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> 
</listener> 

<context-param> 
    <param-name>contextConfigLocation</param-name> 
    <param-value> 
     /WEB-INF/security-context.xml 
    </param-value> 
</context-param> 

<!-- Enables Spring security --> 
<filter> 
    <filter-name>springSecurityFilterChain</filter-name> 
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class> 
</filter> 

<filter-mapping> 
    <filter-name>springSecurityFilterChain</filter-name> 
    <url-pattern>/*</url-pattern> 
</filter-mapping> 

<listener> 
    <listener-class>org.apache.commons.fileupload.servlet.FileCleanerCleanup</listener-class> 
</listener> 

<servlet> 
    <servlet-name>testUI</servlet-name> 
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> 
    <load-on-startup>1</load-on-startup> 
</servlet> 

<servlet-mapping> 
    <servlet-name>testUI</servlet-name> 
    <url-pattern>*.html</url-pattern> 
</servlet-mapping> 

<servlet-mapping> 
    <servlet-name>testUI</servlet-name> 
    <url-pattern>*.form</url-pattern> 
</servlet-mapping> 

<welcome-file-list> 
    <welcome-file>index.jsp</welcome-file> 
</welcome-file-list> 

<jsp-config> 
    <taglib> 
     <taglib-uri>/spring</taglib-uri> 
     <taglib-location>/WEB-INF/tld/spring-form.tld</taglib-location> 
    </taglib> 
</jsp-config> 

하고 여기

<?xml version="1.0" encoding="UTF-8"?> 
<beans xmlns="http://www.springframework.org/schema/beans" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"  
    xmlns:security="http://www.springframework.org/schema/security" 
xsi:schemaLocation="http://www.springframework.org/schema/beans 
         http://www.springframework.org/schema/beans/spring-beans-2.5.xsd 
         http://www.springframework.org/schema/security 
         http://www.springframework.org/schema/security/spring-security-2.0.xsd"> 

<security:global-method-security 
    secured-annotations="enabled" /> 

<security:http auto-config="true"> 
    <!-- Restrict URLs based on role --> 
    <security:intercept-url pattern="/login*" 
     access="IS_AUTHENTICATED_ANONYMOUSLY" /> 
    <security:intercept-url pattern="/logoutSuccess*" 
     access="IS_AUTHENTICATED_ANONYMOUSLY" /> 

    <security:intercept-url pattern="/css/main.css" 
     access="IS_AUTHENTICATED_ANONYMOUSLY" /> 

    <security:intercept-url pattern="/**" access="ROLE_USER" /> 

    <!-- Override default login and logout pages --> 
    <security:form-login login-page="/login.html" 
     login-processing-url="/login.html" default-target-url="/index.jsp" 
     authentication-failure-url="/login.jsp?login_error=1" /> 
    <security:logout logout-url="/logout" 
     logout-success-url="/login.html" /> 
</security:http> 

<security:authentication-provider> 
    <security:jdbc-user-service 
     data-source-ref="dataSource" /> 


</security:authentication-provider> 

전쟁 배포 실패

이있다 모든 로그에 있습니다 :

Feb 16, 2010 11:46:29 AM org.apache.catalina.core.StandardContext start 
SEVERE: Error listenerStart 

이것은 분명히 내 청취자가 실패하게 만드는 원인이지만, 나는 이유를 모르겠습니다.

이것은 Spring Security 2.5와 함께 Tomcat 6.0.20과 Spring MVC 2.5에 배포 중이다.

Answer 1

'datasource'bean이 security-context.xml 파일에 정의되지 않았습니까?

security-context.xml이 WAR 내부의 올바른 위치에 있는지 확인하십시오. web.xml은 /WEB-INF/security-context.xml에 있어야합니다. - tomcat의 분해 된 디렉토리를 확인하십시오. 그것이 실제로 있는지보십시오. 다른 로그 파일의 실제 스택 트레이스에 대한

HTH

Answer 2

<servlet> 
    <servlet-name>testUI</servlet-name> 
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> 
    <init-param> 
     <param-name>contextConfigLocation</param-name> 
     <param-value></param-value> 
    </init-param> 
    <load-on-startup>1</load-on-startup> 
</servlet>