-3
왜 아래 코드에서 데이터가 반환되지 않습니까?
SELECT *
FROM (SELECT p_code, short_name,qty_stock
FROM sample_new.daily_stock)
PIVOT (sum(qty_stock) AS sum_quantity FOR (short_name) IN
(SELECT DISTINCT short_name FROM sample_new.daily_stock));
어쩌면 반환? 질의하는 샘플을 제공하십시오. – Takarii