안녕하세요, 웹 서버에서 데이터를 가져 오기 위해 안드로이드 발리와 json을 사용하여 데이터를 검색하는 중 문제가 발생했습니다.java.lang.String 유형의 값을 Response.Listener에서 JSONObject로 변환 할 수 없습니다.
을 heres 내 PHP 파일 :
<?php
$con = mysqli_connect("***", "***", "***", "***");
// listing input entries for query
$city = $_POST["city"];
$term = $_POST["term"];
$p_type = $_POST["property_type"];
$min = $_POST["price_min"];
$max = $_POST["price_max"];
$bedrooms = $_POST["bedrooms"];
$bathrooms = $_POST["bathrooms"];
$query = "SELECT * FROM listing WHERE city = ? AND term = ? AND property_type = ? AND bedrooms = ? AND bathrooms = ?
AND price BETWEEN ? AND ?";
$statement = mysqli_prepare($con, $query);
mysqli_bind_param($statement, "sssiiii", $city, $term, $p_type, $bedrooms, $bathrooms, $min, $max);
mysqli_stmt_execute($statement);
mysqli_stmt_store_result($statement);
mysqli_stmt_bind_result($statement, $p_id, $p_name, $p_type, $term, $city, $address, $lot_area, $floor_area, $price,
$bedrooms, $bathrooms, $host_name, $host_contact_no, $host_details, $date_listed, $user_id);
$count = mysqli_stmt_num_rows($statement);
mysqli_stmt_close($statement);
$response = array();
$response["hasData"] = false;
if($count > 0){
$response["hasData"] = true;
while(mysqli_stmt_fetch($statement)){
$response["property_name"]= $p_id;
$response["property_type"] = $p_type;
$response["term"] = $term;
$response["city"] = $city;
$response["address"] = $address;
$response["lot_area"] = $lot_area;
$response["floor_area"] = $floor_area;
$response["price"] = $price;
$response["bedroom"] = $bedroom;
$response["bathroom"] = $bathroom;
$response["host_name"] = $host_name;
$response["host_contact_no"] = $host_contact_no;
$response["host_details"] = $host_details;
$response["date_listed"] = $date_listed;
}
}else{
$response["hasData"] = false;
}
echo json_encode($response);
?>
내가 자바 클래스 이름 searchListingRequest.java에게이
public class SearchListingRequest extends StringRequest {
private static final String SEARCH_REQUEST_URL = "http://homeseek.netau.net/searchLising.php";
private Map<String, String> params;
public SearchListingRequest(String city, String term, String p_type,
int price_min, int price_max, int bedrooms, int bathrooms, Response.Listener<String> listener){
super(Method.POST, SEARCH_REQUEST_URL, listener, null);
params = new HashMap<>();
params.put("city", city);
params.put("term", term);
params.put("property_type", p_type);
params.put("price_min", price_min + "");
params.put("price_max", price_max + "");
params.put("bedrooms", bedrooms + "");
params.put("bathrooms", bathrooms + "");
}
@Override
public Map<String, String> getParams() {
return params;
}
}
내 다른 클래스 ShowResults.java에 내가 위의 클래스 인스턴스를 생성하기 위해 전화
http 요청 :@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_show_results);
//unfocus on edittexts when starting
this.getWindow().setSoftInputMode(WindowManager.LayoutParams.SOFT_INPUT_STATE_ALWAYS_HIDDEN);
//gets data from home fragment
Intent intent = getIntent();
//initialize listview
data_listing = (ListView) findViewById(R.id.lv_data_listing);
retrieveData(showResults, intent, data_listing);
}
public void retrieveData(Activity activity,Intent intent, final ListView lv){
final String inputCity = intent.getStringExtra("city");
final String inputTerm = intent.getStringExtra("term");
final String inputType = intent.getStringExtra("type");
final int inputPMin = Integer.parseInt(intent.getStringExtra("price_min"));
final int inputPMax = Integer.parseInt(intent.getStringExtra("price_max"));
final int inputBedrooms = Integer.parseInt(intent.getStringExtra("bedrooms"));
final int inputBathrooms = Integer.parseInt(intent.getStringExtra("bathrooms"));
test = (TextView) findViewById(R.id.tv_test);
Response.Listener<String> responseListener = new Response.Listener<String>() {
@Override
public void onResponse(String response) {
try {
JSONObject jsonResponse = new JSONObject(response);
JSONArray responseArray = new JSONArray(response);
boolean hasData = jsonResponse.getBoolean("hasData");
// check if has data
if(hasData){
test.setText("have data");
}
else{// no data retrieved
showAlertDialog();
test.setText("no data");
}
} catch (JSONException e) {
e.printStackTrace();
Toast.makeText(getApplicationContext(), "Can't connect to server.", Toast.LENGTH_SHORT).show();
test.setText("error");
}
}
};
SearchListingRequest searchListingRequest =
new SearchListingRequest(inputCity,inputTerm,inputType,inputPMin,inputPMax,inputBedrooms,inputBathrooms,responseListener);
RequestQueue queue = Volley.newRequestQueue(getApplicationContext());
queue.add(searchListingRequest);
}
내가 애플리케이션을 실행할 때 텍스트에 "err 또는 "그것은 jsonexception이 있음을 의미합니다.
Value <!DOCTYPE of type java.lang.String cannot be converted to JSONObject
난 정말이게 무슨 뜻인지 모르겠어요 :
여기에 로그 캣입니다. 도와 줘서 고맙다!
응답을 붙여 넣을 수 있습니까? –
당신은 PHP 파일을 의미합니까? –
JsonObjectRequest 메이트를 사용하거나 필요에 따라 잘 확장하십시오. – Memme