@RequestMapping in Spring

Question

나는이 프로그램을 가지고있어 사용자가 로그인하면 보조 페이지를 표시하려고합니다. 첫 번째 화면이 처리됩니다. LoginInterfaceController에 의해 아래 그림과 같이됩니다.

@Controller 
public class LoginInterfaceController{ 

protected final Log logger = LogFactory.getLog(getClass()); 
@RequestMapping 
public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response) 
     throws ServletException, IOException { 

    ModelMap model = new ModelMap(); 
    logger.info("Returning Login View"); 

    model.addAttribute(getLoginAttempt()); 

    return new ModelAndView("LoginView.jsp", model); 
} 

@ModelAttribute("LoginAttempt") 
public LoginAttempt getLoginAttempt() { 
    return new LoginAttempt(); 
} 

@RequestMapping(method=RequestMethod.POST) 
public String validateLogin(@ModelAttribute("LoginAttempt") @Valid LoginAttempt loginDetails, 
     BindingResult bindingResult, Model model, 
     @RequestParam(value="username", required=true) String username, 
     @RequestParam (value="password", required=true) String password) 
{ 
    String returnString; 
    LoginAttempt checkLogin = new LoginAttempt(username, password); 

    if(bindingResult.hasErrors()) 
    { 
     returnString = "LoginView.jsp"; 
    } 
    else if((!checkLogin.getUsername().equalsIgnoreCase("james") || !checkLogin.getPassword().equals("asdf123"))) 
    { 
     returnString = "FailedLogin.jsp"; 
    } 
    else 
    { 
     returnString = "redirect:" + "/ReferrerHome/"; 
    } 
    return returnString; 
} 

사용자의 유효성을 검사하면/Referrer 홈/페이지로 리디렉션해야합니다. 사용자가 인증 그러나

@Controller 
public class LeadInterfaceController { 

private LeadServiceClass leadService = new LeadServiceClass(); 
protected final Log4JLogger logger = new Log4JLogger(); 

@RequestMapping(value="/ReferrerHome/") 
public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response) 
     throws ServletException, IOException { 
    ModelMap model = new ModelMap(); 
    logger.info("Returning Referrer Home View"); 

    model.addAttribute(getLead()); 
    model.addAttribute(getBrokerList()); 
    return new ModelAndView("home.jsp", model); 
} 

@ModelAttribute("Lead") 
private Lead getLead() { 
    return leadService.getNewLead(); 
} 
@ModelAttribute("Broker") 
private ArrayList<Broker> getBrokerList(/*Referrer referrer*/) 
{ 
    return /*(ArrayList<Broker>)referrer.getBrokers() */ new ArrayList<Broker>(); 
} 

@RequestMapping(value="ReferrerHome/home.jsp", method=RequestMethod.POST) 
public String validateLogin(@ModelAttribute("Lead") @Valid Lead leadInput, BindingResult bindingResult, Model model)    
{ 
    String returnString; 
    if(leadInput.getLeadHomePhoneNumber() == null && 
      leadInput.getLeadWorkPhoneNumber() == null && 
      leadInput.getLeadMobilePhoneNumber() == null && 
      leadInput.getLeadEmail() == null){ 
     logger.info("HPhoneNum: " + leadInput.getLeadHomePhoneNumber()); 
     //code here to set an error state indicating that some contact information is required 
    } 
    if(bindingResult.hasErrors()) 
    { 
     returnString = "ReferrerHome/home.jsp"; 
    } 
    else 
    { 
     leadService.getLeadDao().addLead(leadInput); 
     returnString = "ReferrerHome/success.jsp"; 
    } 
    return returnString; 
} 

/ReferrerHome에 URL 스위치 다음 /하지만 LoginView.jsp 대신 home.jsp로드 될 리로드로

내 LeadInterfaceController 세트는 요청 매핑을 갖는다. 분노한 것은 이틀 전에 일하는 것이었고, 내가 깰 수 있었던 것을 생각할 수 없다는 것입니다.

는 여기

<?xml version="1.0" encoding="UTF-8"?> 
<beans xmlns="http://www.springframework.org/schema/beans" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc" 
xmlns:context="http://www.springframework.org/schema/context" 
xmlns:jdbc="http://www.springframework.org/schema/jdbc" xmlns:tx="http://www.springframework.org/schema/tx" 
xsi:schemaLocation="http://www.springframework.org/schema/jdbc http://www.springframework.org/schema/jdbc/spring-jdbc-3.1.xsd 
    http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd 
    http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd 
    http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.1.xsd 
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.1.xsd"> 
<mvc:resources mapping="/resources/**" location="/resources/" /> 
<mvc:annotation-driven /> 
<tx:annotation-driven/> 
<jdbc:embedded-database id="LTSDatabase" type="HSQL" /> 
<context:component-scan base-package="com.au.curtin" /> 
<import resource="*/WEB-INF/classes/com/au/curtin/leadtrackingsystem.xml" /> 

<bean id="sessionFactory" 
    class="org.springframework.orm.hibernate4.LocalSessionFactoryBean"> 
    <property name="dataSource" ref="LTSDatabase" /> 
    <property name="hibernateProperties"> 
     <props> 
      <prop key="hibernate.dialect">org.hibernate.dialect.HSQLDialect</prop> 
      <prop key="hibernate.current_session_context_class">thread</prop> 
      <prop key="hibernate.transaction.factory_class">org.hibernate.transaction.JDBCTransactionFactory 
      </prop> 
      <prop key="hibernate.show_sql">true</prop> 
      <prop key="hibernate.hbm2ddl.auto">update</prop> 
     </props> 
    </property> 
</bean> 
<bean id="PersistenceAnnotationPostProcessor" 
    class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" /> 
<bean id="hibernateExceptionTranslator" 
    class="org.springframework.orm.hibernate4.HibernateExceptionTranslator" /> 
<bean 
    class="org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor" 
    id="PersistenceExceptionTranslator" depends-on="hibernateExceptionTranslator" /> 

<bean id="transactionManager" 
    class="org.springframework.orm.hibernate4.HibernateTransactionManager"> 
    <property name="sessionFactory" ref="sessionFactory" /> 
</bean> 
<bean id="viewResolver" 
    class="org.springframework.web.servlet.view.InternalResourceViewResolver"> 
    <property name="viewClass" 
     value="org.springframework.web.servlet.view.JstlView" /> 
    <property name="prefix" value="/WEB-INF/jsp/" /> 
    <property name="suffix" value="" /> 
</bean> 

내 LTSServlet.xml 여기 내 web.xml을

<?xml version="1.0" encoding="UTF-8"?> 
    <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns="http://java.sun.com/xml/ns/javaee" 
    xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0"> 
    <servlet> 
    <servlet-name>LTSServlet</servlet-name> 
    <servlet-class> 
     org.springframework.web.servlet.DispatcherServlet 
    </servlet-class> 
    <load-on-startup>1</load-on-startup> 
    </servlet> 
    <servlet-mapping> 
    <servlet-name>LTSServlet</servlet-name> 
    <url-pattern>*.htm</url-pattern> 
    </servlet-mapping> 
    <welcome-file-list> 
    <welcome-file>LoginView.htm</welcome-file> 
    </welcome-file-list> 
    </web-app> 

나는이 작업을 얻으려고 내 머리를 찢어하고 있습니다.

희망 하시겠습니까?

Answer 1

validateLogin (요청 유형 만)에 경로 매핑이 없습니다. 따라서 "home.jsp"를 반환하면 validateLogin으로 매핑되고 @RequestMapping(value="ReferrerHome/home.jsp", method=RequestMethod.POST)으로 매핑되지 않습니다.

시도 : home.jsp 대신 ReferrerHome/home.jsp을 LeadInterfaceController.handleRequest에 반환하십시오. 2. validateLogin의 매핑을 바운드 된 경로가 포함되도록 변경합니다. 그러면 리디렉션 후에 버그를 설명하는 오류가 발생할 수 있습니다.

도움이됩니다.

DispatcherServlet에서 디버거를 사용하고 흐름 ("login.jsp"페이지 선택 방법)을 수행 할 수도 있습니다.