왜 JPARepositoryImpl 코드가 호출되지 않습니까?

Question

다음과 같은 간단한 스프링 부트 코드가 있습니다. 왜 JPARepositoryImpl 코드 - JpaCustomerRepository가 호출되지 않습니다 (print 문을 추가하여 ..).

주 및 컨트롤러에 @ComponentScan을 추가했습니다. 제발 조언.

감사합니다,

@Entity 
    public class Customer implements Serializable { 

     private static final long serialVersionUID = 1L; 

     @Id 
     @GeneratedValue 
     private Long id; 

     @Column(nullable = false) 
     private String product; 

     @Column(nullable = false) 
     private String charge; 

     protected Customer() { 
     } 

     public Customer(String product) { 
      this.product = product; 
     } 

     public Long getId() { 
      return id; 
     } 

     public String getProduct() { 
      return this.product; 
     } 


     public String getCharge() { 
      return this.charge; 
     }} 


    public interface CustomerRepository extends Repository<Customer, Long> { 

      List<Customer> findAll(); 

     } 

     @Repository 
     class JpaCustomerRepository implements CustomerRepository { 

      @PersistenceContext 
      private EntityManager em; 

      @Override 
      public List<Customer> findAll() { 
       TypedQuery<Customer> query = em.createQuery("select c from Customer c", 
         Customer.class); 

       return query.getResultList(); 
      } 


     } 

@Configuration 
@ComponentScan 
@EnableAutoConfiguration 
public class SampleDataJpaApplication { 

    public static void main(String[] args) throws Exception { 
     SpringApplication.run(SampleDataJpaApplication.class, args); 
    } 

} 
@Controller 
@ComponentScan 
@RequestMapping("/customers") 
public class SampleController { 
    private CustomerRepository customerRepository; 

    @Autowired 
    public SampleController(CustomerRepository customerRepository) { 
     this.customerRepository = customerRepository; 
    } 

    @RequestMapping("/list") 
    public String list(Model model) { 
     model.addAttribute("customers", this.customerRepository.findAll()); 
     return "customers/list"; 
    } 


} 

그러나 책 봄 데이터의 샘플 코드 (JpaCustomerRepository가) 전화를받을 않았다. 그 잡은 거니?

@MappedSuperclass 
public class AbstractEntity { 

    @Id 
    @GeneratedValue(strategy = GenerationType.AUTO) 
    private Long id; 

    /** 
    * Returns the identifier of the entity. 
    * 
    * @return the id 
    */ 
    public Long getId() { 
     return id; 
    } 

    /* 
    * (non-Javadoc) 
    * @see java.lang.Object#equals(java.lang.Object) 
    */ 
    @Override 
    public boolean equals(Object obj) { 

     if (this == obj) { 
      return true; 
     } 

     if (this.id == null || obj == null || !(this.getClass().equals(obj.getClass()))) { 
      return false; 
     } 

     AbstractEntity that = (AbstractEntity) obj; 

     return this.id.equals(that.getId()); 
    } 

    /* 
    * (non-Javadoc) 
    * @see java.lang.Object#hashCode() 
    */ 
    @Override 
    public int hashCode() { 
     return id == null ? 0 : id.hashCode(); 
    } 
} 
    @Entity 
    public class Customer extends AbstractEntity { 

     private String firstname, lastname; 

     @Column(unique = true) 
     private EmailAddress emailAddress; 

     @OneToMany(cascade = CascadeType.ALL, orphanRemoval = true) 
     @JoinColumn(name = "customer_id") 
     private Set<Address> addresses = new HashSet<Address>(); 

     /** 
     * Creates a new {@link Customer} from the given firstname and lastname. 
     * 
     * @param firstname must not be {@literal null} or empty. 
     * @param lastname must not be {@literal null} or empty. 
     */ 
     public Customer(String firstname, String lastname) { 

      Assert.hasText(firstname); 
      Assert.hasText(lastname); 

      this.firstname = firstname; 
      this.lastname = lastname; 
     } 

     protected Customer() { 

     } 

     /** 
     * Adds the given {@link Address} to the {@link Customer}. 
     * 
     * @param address must not be {@literal null}. 
     */ 
     public void add(Address address) { 

      Assert.notNull(address); 
      this.addresses.add(address); 
     } 

     /** 
     * Returns the firstname of the {@link Customer}. 
     * 
     * @return 
     */ 
     public String getFirstname() { 
      return firstname; 
     } 

     /** 
     * Returns the lastname of the {@link Customer}. 
     * 
     * @return 
     */ 
     public String getLastname() { 
      return lastname; 
     } 

     /** 
     * Sets the lastname of the {@link Customer}. 
     * 
     * @param lastname 
     */ 
     public void setLastname(String lastname) { 
      this.lastname = lastname; 
     } 

     /** 
     * Returns the {@link EmailAddress} of the {@link Customer}. 
     * 
     * @return 
     */ 
     public EmailAddress getEmailAddress() { 
      return emailAddress; 
     } 

     /** 
     * Sets the {@link Customer}'s {@link EmailAddress}. 
     * 
     * @param emailAddress must not be {@literal null}. 
     */ 
     public void setEmailAddress(EmailAddress emailAddress) { 
      this.emailAddress = emailAddress; 
     } 

     /** 
     * Return the {@link Customer}'s addresses. 
     * 
     * @return 
     */ 
     public Set<Address> getAddresses() { 
      return Collections.unmodifiableSet(addresses); 
     } 
    } 
    public interface CustomerRepository extends Repository<Customer, Long> { 

     /** 
     * Returns the {@link Customer} with the given identifier. 
     * 
     * @param id the id to search for. 
     * @return 
     */ 
     Customer findOne(Long id); 

     /** 
     * Saves the given {@link Customer}. 
     * 
     * @param customer the {@link Customer} to search for. 
     * @return 
     */ 
     Customer save(Customer customer); 

     /** 
     * Returns the customer with the given {@link EmailAddress}. 
     * 
     * @param emailAddress the {@link EmailAddress} to search for. 
     * @return 
     */ 
     Customer findByEmailAddress(EmailAddress emailAddress); 
    } 
    @Repository 
    class JpaCustomerRepository implements CustomerRepository { 

     @PersistenceContext 
     private EntityManager em; 

     /* 
     * (non-Javadoc) 
     * @see com.oreilly.springdata.jpa.core.CustomerRepository#findOne(java.lang.Long) 
     */ 
     @Override 
     public Customer findOne(Long id) { 
      return em.find(Customer.class, id); 
     } 

     /* 
     * (non-Javadoc) 
     * @see com.oreilly.springdata.jpa.core.CustomerRepository#save(com.oreilly.springdata.jpa.core.Customer) 
     */ 
     public Customer save(Customer customer) { 
      if (customer.getId() == null) { 
       em.persist(customer); 
       return customer; 
      } else { 
       return em.merge(customer); 
      } 
     } 

     /* 
     * (non-Javadoc) 
     * @see com.oreilly.springdata.jpa.core.CustomerRepository#findByEmailAddress(com.oreilly.springdata.jpa.core.EmailAddress) 
     */ 
     @Override 
     public Customer findByEmailAddress(EmailAddress emailAddress) { 
      TypedQuery<Customer> query = em.createQuery("select c from Customer c where c.emailAddress = :email", 
        Customer.class); 
      query.setParameter("email", emailAddress); 

      return query.getSingleResult(); 
     } 
    } 

원본 코드 시험 방법,

@ContextConfiguration(classes = PlainJpaConfig.class) 
public class JpaCustomerRepositoryIntegrationTest extends AbstractIntegrationTest { 

    @Autowired 
    CustomerRepository repository; 

    @Test 
    public void insertsNewCustomerCorrectly() { 

     Customer customer = new Customer("Alicia", "Keys"); 
     customer = repository.save(customer); 

     assertThat(customer.getId(), is(notNullValue())); 
    } 

    @Test 
    public void updatesCustomerCorrectly() { 

     Customer dave = repository.findByFirstname("Dave"); 
     assertThat(dave, is(notNullValue())); 

     dave.setLastname("Miller"); 
     dave = repository.save(dave); 

     Customer reference = repository.findByFirstname(dave.getFirstname()); 
     assertThat(reference.getLastname(), is(dave.getLastname())); 
    } 
} 

내 주요 방법 코드,

@Configuration 
@ComponentScan 
@EnableAutoConfiguration 
@ContextConfiguration(classes = PlainJpaConfig.class) 
public class SampleDataJpaApplication { 

    public static void main(String[] args) throws Exception { 
     SpringApplication.run(SampleDataJpaApplication.class, args); 
    } 

} 

나는 원래 코드가 추가 @EnableAutoConfiguration이없는 한 어떤? 이것이 이유일까요? 하지만 @EnableAutoConfiguration이 없으면 스프링 부트 컨테이너를 시작할 수 없습니다.

Answer 1

스프링 데이터가 CustomerRepository에 대한 구현을 동적으로 제공하기 때문에 코드가 호출되지 않습니다. 귀하의 코드는 중복됩니다 (스프링 데이터가 자동으로 처리 할 수없는 일을하지 않는다는 의미에서). 그러나 스프링 데이터가 제공하는 구현을 자동으로 생성 할 수없는 코드로 보완 할 수있는 방법을 알고 싶다면 체크 아웃하십시오. documentation.