의 MySQL : 쿼리가 다른 컬럼의 속성에 따라 데이터를 정렬하는

Question

그래서,이 제목과 함께 오는

SELECT Date(p.born_at), SUM(p.value) as 'total_value_for_day' 
FROM puppies as p 
WHERE p.status = 2 
GROUP BY DATE(p.born_at); 

그래서, 이것은 2 열 결과를 제공 어렵다.

열 :

date | status = 1 | status = 2 | status = 3 
DATA!!! 

그렇게 할 수있는 방법이

내가 원하는이 무엇입니까?

Answer 1

SELECT Date(p.born_at), 
SUM(case when status = 1 then p.value end) as 'status = 1', 
SUM(case when status = 2 then p.value end) as 'status = 2', 
SUM(case when status = 3 then p.value end) as 'status = 3' 
FROM puppies as p 
WHERE p.status in(1,2,3) 
GROUP BY DATE(p.born_at); 

Answer 2

SELECT Date(born_at), 
    SUM(case when Status = 1 then value else 0 end) as 'status = 1', 
    SUM(case when Status = 2 then value else 0 end) as 'status = 2', 
    SUM(case when Status = 3 then value else 0 end) as 'status = 3' 
FROM puppies 
GROUP BY DATE(born_at); 

Answer 3

SELECT 
    DATE(p.born_at) 
    , SUM(CASE WHEN STATUS = 1 THEN p.value END) AS 'Status = 1' 
    , SUM(CASE WHEN STATUS = 2 THEN p.value END) AS 'Status = 2' 
    , SUM(CASE WHEN STATUS = 3 THEN p.value END) AS 'Status = 3' 
FROM puppies AS p 
WHERE p.status IN(1, 2, 3) 
GROUP BY DATE(p.born_at);