-1
10 초 이상 실행되는 쿼리가 있습니다. 다음 쿼리를 즉석에서 수행 할 수있는 몇 가지 제안을하십시오!MYSQL에서 유니온 최적화하기
CREATE TABLE uem_map_user_event (
id INT(11) , uem_user_id INt(10),uem_event_type_id INT(11),
uem_entry_date DATETIME ,INDEX urt_user_id (uem_user_id));
CREATE TABLE evy_mst_event_type (id INT(11) , evy_description VARCHAR(45),
evy_event_family_id INT(11),PRIMARY KEY (id));
CREATE TABLE uft_map_user_clnt (
id INT(11) ,uft_user_id INT(11) ,uft_clnt_id INT(11) ,uft_eff_frmdt DATETIME ,
uft_eff_todt DATETIME ,uft_add_userid INT(11) ,uft_mod_userid INT(11));
select * from (
select u.id as id,evy.description as 'Work Description',count(*) as Pending
from user_event u
join event_type evy on evy.id = u.event_type_id
join (select fun.eventtypeid ,fun.client_id ,uft.user_id
from vw_fund_queue fun
join uft_clnt uft on uft.uft_clnt_id = fun.client_id
) evt on evy.id = evt.eventtypeid
and u.user_id = evt.user_id
where evy.id = 1601 and u.user_id = 10061
union all
select u.id as id,evy.description as 'Work Description',count(*) as Pending
from user_event u
join event_type evy on evy.id = u.event_type_id
join (select fun.eventtypeid ,fun.client_id ,uft.user_id
from vw_fund_confirm fun
join uft_clnt uft on uft.uft_clnt_id = fun.client_id
) evt on evy.id = evt.eventtypeid
and u.user_id = evt.user_id
where evy.id = 1201 and u.user_id = 10061
union all
select u.id as id,evy.description as 'Work Description',count(*) as Pending
from user_event u
join event_type evy on evy.id = u.event_type_id
join (select fun.eventtypeid ,fun.client_id ,uft.user_id
from vw_fund_approve fun
join uft_user_clnt uft on uft.clnt_id = fun.client_id
) evt on evy.id = evt.eventtypeid
and uem.user_id = evt.user_id
where evy.id = 1202 and u.user_id = 10061) a where a.pending!=0
조차 질문, 단지 명령을? – Nanne
한계 1을 사용하면 정확히 하나의 레코드를 찾을 수 있습니다. –
'EXPLAIN EXTENDED'기능을 사용해보십시오. – DaSourcerer