둘러 보았고 다음에 대한 답을 찾을 수 없습니다.쿼리의 다른 테이블에 값이 없는지 확인합니다.
원하는 것은 SQL select 문을 실행하는 것입니다.
는$query = mysql_query("SELECT `ordate`, `invno` FROM `armast09` WHERE cshipno = '$username' AND `ordate` > DATE_SUB(CURDATE(), INTERVAL 4 DAY)") or die(header("location:index.php?e=4"));
$numrows = mysql_num_rows($query);
$date = date('o-n-d');
include 'indexfiles/top.php';
echo "The following deliveries are available for viewing/dispute:";
echo "<br />";
echo "<br />";
echo "<center>";
echo "<table>";
if($numrows != 0) {
while ($info = mysql_fetch_array($query)) {
echo "<tr>";
echo "<form action = \"deliverydispute.php?invno=".$info['invno']."\" method=\"POST\ onsubmit=\"return confirm('Are you sure you are ready to dispute? You can't go back after this.');\">";
echo "<td><b>Invoice Number: </b>".$info['invno']."</td>";
echo "<td><b>Order Date: </b>".$info['ordate']."</td>";
echo "<td><a href = \"deliverydispute.php?invno=".$info['invno']."&&ordate=".$info['ordate']."\">Dispute</a></td>";
echo "</form>";
echo "</tr>";
}
} else {
echo ("<font color=\"red\" face=\"arial\" size=\"2\"><small>No orders are currently available for viewing.</small></font>");
}
echo "</table>";
mysql 확장을 사용하면 안됩니다. 이유와 대안은 http://php.net/en/mysql-connect – KingCrunch