0
SELECT p1.*,
(p1.opening_balance + p1.retained_now - p1.released_now -
p1.clawbacked_amount - p1.arrears_amount) AS closing_balance
FROM (SELECT p.channel_org_id,
t.channel_name,
p.aggregation_id,
((SELECT SUM(amount)
FROM t_agent_retention_balance
WHERE agent_id IN
(SELECT agent_id
FROM t_agent
WHERE channel_org_id = p.channel_org_id)
AND account_type = 5) -
(SELECT SUM(commision)
FROM t_product_commision
WHERE aggregation_id < p.aggregation_id
AND channel_org_id = p.channel_org_id
AND commision_type_id = 1104) +
(SELECT SUM(commision)
FROM t_product_commision
WHERE aggregation_id < p.aggregation_id
AND channel_org_id = p.channel_org_id
AND commision_type_id = 1110) +
(SELECT SUM(commision)
FROM t_product_commision
WHERE aggregation_id < p.aggregation_id
AND channel_org_id = p.channel_org_id
AND commision_type_id = 1122) +
(SELECT SUM(commision)
FROM t_product_commision
WHERE aggregation_id < p.aggregation_id
AND channel_org_id = p.channel_org_id
AND commision_type_id = 1123)
) AS opening_balance,
(SELECT SUM(commision)
FROM t_product_commision
WHERE aggregation_id = p.aggregation_id
AND channel_org_id = p.channel_org_id
AND commision_type_id = 1104) AS retained_now,
(SELECT SUM(commision)
FROM t_product_commision
WHERE aggregation_id = p.aggregation_id
AND channel_org_id = p.channel_org_id
AND commision_type_id = 1110) AS released_now,
(SELECT SUM(commision)
FROM t_product_commision
WHERE aggregation_id = p.aggregation_id
AND channel_org_id = p.channel_org_id
AND commision_type_id = 1122) AS clawbacked_amount,
(SELECT SUM(commision)
FROM t_product_commision
WHERE aggregation_id = p.aggregation_id
AND channel_org_id = p.channel_org_id
AND commision_type_id = 1123) AS arrears_amount
FROM t_product_commision p, t_channel_org t, t_commision_type ct
WHERE t.channel_id = p.channel_org_id
AND p.commision_type_id = ct.commision_type_id
AND p.aggregation_id =?
AND p.comm_status <> 1
AND p.channel_org_id = ?
GROUP BY p.channel_org_id, t.channel_name, p.aggregation_id) p1
값을 전달 하시겠습니까? p1 임시 테이블의 매개 변수는 어떻게 이것을 달성 할 수 있습니까 ? 장소 내가 p1.x를 전달하고 싶습니다. 그리고 p1.x와 같은 값을 전달하려고 시도하면 p1.x 후where p1.x=12 and p1.y=23
입니다. p1.x가 유효하지 않음을 나타냅니다.임시 테이블에 값을 전달하는 방법
도움이 되셨습니까? http://stackoverflow.com/questions/2236201/how-can-i-pass-parameter-to-sql-script – Jester
질문이 명확하지 않습니다. '안에? p1.x '를 전달하고자하는 장소,'? '표시 중 하나를'p1'의 열 중 하나로 바꾸는 것을 의미합니까? 'p.aggregation_id = p1.released_now'? (필자는이 예제가 반드시 필요한 것은 아닌지 잘 모르겠다.) 'p1 이후에 p1.x = 12와 같은 값을 전달하려고했다'는 말은 'p1.aggregation_id = 12'와 같은 조건을 추가하려고했다는 뜻인가요? '질의의 끝까지? JDBC를 사용하여'stmt.setString (1, "p1.x")'와 같은 것을 작성하려고합니까? –
예. p1.aggregation_id = 12 ....와 같은 조건을 추가하려고했는데 오류 @luke를 보냈습니다 –