예기치 않은 T_STRING을 찾을 수 없습니다.

Question

일반적으로 T_String 오류는 추가 인용문이 있거나 최소한 생각했습니다. 오늘 나는이 오류

Parse error: syntax error, unexpected T_STRING in /var/www/html/registerBackend.php on line 118 

을 가지고 여기에 도움이된다면 118 + 119 여기

$query = "INSERT INTO User (Name,Email,Password,Port) VALUES ('$name', '$email','$password','$port')"; 
mysql_query($query) or die('Error, insert query failed'); 

좀 더 코드 라인의 코드입니다

$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql'); 

$dbname ='hidden'; 
mysql_select_db($dbname); 

//Check if Username has been used before 
$query = "SELECT * FROM User where Name='$name'"; 
$result=mysql_query($query) or die('Error, insert query failed'); 
$countName=mysql_num_rows($result); 

//Check if email has been used before 
$query = "SELECT * FROM User where Email='$email'"; 
$result=mysql_query($query) or die('Error, insert query failed'); 
$countEmail=mysql_num_rows($result); 

if($countName < 1 && $countEmail < 1){ 

//Assign their port number 
$query = "SELECT * FROM login; 
$countPort=mysql_num_rows($result); 
$port = 20000 + $countPort; 


$query = "INSERT INTO User (Name,Email,Password,Port) VALUES ('$name', '$email','$password','$port')"; 
mysql_query($query) or die('Error, insert query failed'); 


$query = "SELECT username, password FROM login WHERE username = '$username' AND password = '$password'"; 
$result = mysql_query($query); 

print "<center><div id=newAREA>You have been signed up!<br>"; 
while($row = mysql_fetch_array($result, MYSQL_ASSOC)){ 
    echo "Minecraft Username:{$row['Name']} <br>" . 
     "Email:{$row['Email']} <br>" . 
     "Password:{$row['Password']} <br>". 
     "Port:{$row['Port']} <br>"; 

} 
} elseif ($countName > 1) { 
print "Someone has already used this Minecraft IGN! E-mail Stolen@freeminecrafthost.com to prove it is yours!"; 
} elseif ($countEmail > 1) { 
print "Email has been used before!"; 
} 

Answer 1

해야한다 :

$query = "SELECT * FROM login; 

당신이 필요합니다 :

$query = "SELECT * FROM login"; 

하지만 분명히 이러한 쿼리를 제공해야합니다.

Answer 2

시도

$query = "INSERT INTO User (Name,Email,Password,Port) VALUES ('" . mysql_real_escape_string($name) . "', '" . mysql_real_escape_string($email) . "','" . mysql_real_escape_string($password) . "','" . mysql_real_escape_string($port) . "')"; 
mysql_query($query) or die('Error, insert query failed'); 

업데이트

이 줄

$query = "SELECT * FROM login; 

라인에

$query = "SELECT * FROM login"; 

Answer 3

//Assign their port number 
$query = "SELECT * FROM login; 
$countPort=mysql_num_rows($result); 
$port = 20000 + $countPort; 

login 이후에 견적이 누락되었습니다.

$query = "SELECT * FROM login"; 

칭찬 해주세요!