SQL이 별도의 쿼리를 결합합니다

Question

초보자 용의 질문에 사과드립니다. 그러나 이러한 쿼리를 여러 쿼리가 아닌 하나의 데이터 세트에 어떻게 넣을 수 있습니까? 그들은 모두 동일한 테이블에서 꺼내집니다. 또한 볼 수 있듯이 "Open_Time"이 있습니다. 이것은 DATE 형식입니다. Open_date가 지난 60 일 이내에 어떻게 말합니까?

SELECT COUNT(P_NUMBER) 
FROM PROBLEM_REPORT 
WHERE Assignment='Crosby' 
AND Severity=4 
AND Open_Time<=60; 

SELECT COUNT(P_NUMBER) 
FROM PROBLEM_REPORT 
WHERE Assignment='Crosby' 
AND Severity=5 
AND Open_Time<=60; 

SELECT COUNT(P_NUMBER) 
FROM PROBLEM_REPORT 
WHERE Assignment='Crosby' 
AND Severity=4 
AND Close_Time<=60; 

SELECT COUNT(P_NUMBER) 
FROM PROBLEM_REPORT 
WHERE Assignment='Crosby' 
AND Severity=4 
AND Close_Time<=60; 

SELECT COUNT(P_NUMBER) 
FROM PROBLEM_REPORT 
WHERE Assignment='EUC' 
AND Severity=4 
AND Open_Time<=60; 

SELECT COUNT(P_NUMBER) 
FROM PROBLEM_REPORT 
WHERE Assignment='EUC' 
AND Severity=5 
AND Open_Time<=60; 

SELECT COUNT(P_NUMBER) 
FROM PROBLEM_REPORT 
WHERE Assignment='EUC' 
AND Severity=4 
AND Close_Time<=60; 

SELECT COUNT(P_NUMBER) 
FROM PROBLEM_REPORT 
WHERE Assignment='EUC' 
AND Severity=4 
AND Close_Time<=60; 

Answer 1

이 sql을 사용해보십시오. 이 일을

SELECT COUNT(CASE WHEN Assignment = 'Crosby' AND Severity = 4 AND DATEDIFF(CURDATE(),Open_Time)<=60 THEN P_NUMBER END) as p1, 
    COUNT(CASE WHEN Assignment = 'Crosby' AND Severity = 5 AND DATEDIFF(CURDATE(),Open_Time)<=60 THEN P_NUMBER END) as p2, 
    COUNT(CASE WHEN Assignment = 'Crosby' AND Severity = 4 AND DATEDIFF(CURDATE(),Close_Time)<=60 THEN P_NUMBER END) as p3, 
    COUNT(CASE WHEN Assignment = 'Crosby' AND Severity = 5 AND DATEDIFF(CURDATE(),Close_Time)<=60 THEN P_NUMBER END) as p4, 
    COUNT(CASE WHEN Assignment = 'EUC' AND Severity = 4 AND DATEDIFF(CURDATE(),Open_Time)<=60 THEN P_NUMBER END) as p5, 
    COUNT(CASE WHEN Assignment = 'EUC' AND Severity = 5 AND DATEDIFF(CURDATE(),Open_Time)<=60 THEN P_NUMBER END) as p6, 
    COUNT(CASE WHEN Assignment = 'EUC' AND Severity = 4 AND DATEDIFF(CURDATE(),Close_Time)<=60 THEN P_NUMBER END) as p7, 
    COUNT(CASE WHEN Assignment = 'EUC' AND Severity = 5 AND DATEDIFF(CURDATE(),Close_Time)<=60 THEN P_NUMBER END) as p8 
FROM PROBLEM_REPORT 
WHERE Assignment IN('EUC','Crosby') 
AND Severity IN(4,5) 

Answer 2

한 가지 방법 :

SELECT 
SUM(CASE WHEN Assignment = 'Crosby' AND Severity=4 AND Open_Time<=60 THEN 1 ELSE 0 END) AS P_number1 
,SUM(CASE WHEN Assignment = 'Crosby' AND Severity=5 AND Open_Time<=60 THEN 1 ELSE 0 END) AS P_number2 
,SUM(CASE WHEN Assignment = 'Crosby' AND Severity=4 AND close_time<=60 THEN 1 ELSE 0 END) AS P_number3 
,SUM(CASE WHEN Assignment = 'Crosby' AND Severity=5 AND close_time<=60 THEN 1 ELSE 0 END) AS P_number4 
,SUM(CASE WHEN Assignment = 'EUC' AND Severity=4 AND Open_Time<=60 THEN 1 ELSE 0 END) AS P_number5 
,SUM(CASE WHEN Assignment = 'EUC' AND Severity=5 AND Open_Time<=60 THEN 1 ELSE 0 END) AS P_number6 
,SUM(CASE WHEN Assignment = 'EUC' AND Severity=4 AND close_time<=60 THEN 1 ELSE 0 END) AS P_number7 
,SUM(CASE WHEN Assignment = 'EUC' AND Severity=5 AND close_time<=60 THEN 1 ELSE 0 END) AS P_number8 
FROM PROBLEM_REPORT 

Answer 3

쿼리에 WHERE 절에만 필터링 된 행을 계산하기 때문에 쿼리가 훨씬 더 빨리가 만들 것입니다.

SELECT COUNT(CASE WHEN Assignment = 'Crosby' AND Severity = 4 AND Open_Time <= 60 THEN P_NUMBER END), 
     COUNT(CASE WHEN Assignment = 'Crosby' AND Severity = 5 AND Open_Time <= 60 THEN P_NUMBER END), 
     COUNT(CASE WHEN Assignment = 'Crosby' AND Severity = 4 AND Close_Time <= 60 THEN P_NUMBER END), 
     COUNT(CASE WHEN Assignment = 'Crosby' AND Severity = 5 AND Close_Time <= 60 THEN P_NUMBER END), 
     COUNT(CASE WHEN Assignment = 'EUC' AND Severity = 4 AND Open_Time <= 60 THEN P_NUMBER END), 
     COUNT(CASE WHEN Assignment = 'EUC' AND Severity = 5 AND Open_Time <= 60 THEN P_NUMBER END), 
     COUNT(CASE WHEN Assignment = 'EUC' AND Severity = 4 AND Close_Time <= 60 THEN P_NUMBER END), 
     COUNT(CASE WHEN Assignment = 'EUC' AND Severity = 5 AND Close_Time <= 60 THEN P_NUMBER END) 
FROM PROBLEM_REPORT 
WHERE Assignment IN ('Crosby', 'EUC') AND 
     Severity IN (4,5) AND 
     (Open_Time <= 60 OR Close_Time <= 60)