이가 당신의 요소가
XPathFactory factory = XPathFactory.newInstance();
XPath xpath = factory.newXPath();
Element element = (Element) xpath.evaluate(
"/container/item/xmlText", document, XPathConstants.NODE);
다음 XPath를 함께 검색 할 때, 당신은이 라인을 따라 뭔가를 할 수 :이보다 간결 것
java.io.ByteArrayOutputStream data =
new java.io.ByteArrayOutputStream();
java.io.PrintStream ps = new java.io.PrintStream(data);
// These classes are part of Xerces. But you will find them in your JDK,
// as well, in a different package. Use any encoding here:
org.apache.xml.serialize.OutputFormat of =
new org.apache.xml.serialize.OutputFormat("XML", "ISO-8859-1", true);
org.apache.xml.serialize.XMLSerializer serializer =
new org.apache.xml.serialize.XMLSerializer(ps, of);
// Here, serialize the element that you obtained using your XPath expression.
serializer.asDOMSerializer();
serializer.serialize(element);
// The output stream now holds serialized XML data, including tags/attributes...
return data.toString();
UPDATE, 오히려 Xerces 내부를 사용하는 것보다.
ByteArrayOutputStream out = new ByteArrayOutputStream();
Transformer transformer = TransformerFactory.newInstance().newTransformer();
transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
Source source = new DOMSource(element);
Result target = new StreamResult(out);
transformer.transform(source, target);
return out.toString();
좋은 질문, +1. 짧고 쉬운 XSLT 솔루션에 대한 내 대답을 참조하십시오. :) –