구문 분석 된 json 데이터를 신속하게 배열에 저장하는 방법

Question

그래서 서버에서 일부 json 데이터를 받으면 배열로 저장하려고하므로 tableview를 채울 수 있지만 문제가 발생했습니다. 내 코드 :

class UserInfo : UIViewController{ 
var main = "" 
session.dataTask(with: url) { (data, response, error) in 
     if let response = response { 
      print (response) 
     } 
     if let data = data { 
      let json = (try? JSONSerialization.jsonObject(with: data, options: [])) 
      print(json) 
      guard let array = json as? [Any] else {return} 
      for info in array { 
      guard let infoDict = info as? [String : Any] else{return} 
      //there is a declared var called main 
      //main is the one i want save as an array, currently its a variable. i tried to save it as an array by using as! Array but i get error 
      self.main = infoDict["Title"] as! String 
      print (self.main) 
} 
} 
}.resume() 
} 

Answer 1

먼저 범위 ary을 선언해야합니다. 그런 다음 데이터를 동일한 ary에 저장해야합니다.

var ary: NSMutableArray = NSMutableArray() 

session.dataTask(with: url) { (data, response, error) in 
      if let response = response { 
       print (response) 
      } 
      if let data = data { 
       let json = (try? JSONSerialization.jsonObject(with: data, options: [])) 
       print(json) 
       guard let array = json as? [Any] else {return} 
       for info in array { 
        guard let infoDict = info as? [String : Any] else{return} 
        //there is a declared var called main 
        //main is the one i want save as an array, currently its a variable. i tried to save it as an array by using as! Array but i get error 
        self.main = infoDict["Title"] as! String 
        self.ary.add(self.main) 
        print (self.main) 
       } 
       print("Final array is :::",self.ary) 
      } 
      }.resume() 

위 코드를 시도해보십시오. 희망이 당신을 위해 작동합니다.