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그래서이 방법을 사용하고 마지막 줄에서 samAccountName을 얻으려는 곳에서 저에게 COM 예외를 던져서 저를 미쳤습니다.광고 쿼리, 서버가 작동하지 않습니다.
아이디어가 있으십니까?
public User FindUsername(string samAccountName, string groupDisplayName)
{
using (DirectoryEntry searchRoot = new DirectoryEntry(ldapf, ldapu, ldapp))
{
using (DirectorySearcher searcher = new DirectorySearcher(searchRoot))
{
searcher.Asynchronous = false;
searcher.PropertiesToLoad.Add("SAMAccountName");
searcher.PropertiesToLoad.Add("displayName");
searcher.PropertiesToLoad.Add("uSNChanged");
searcher.PropertiesToLoad.Add("member");
searcher.PropertiesToLoad.Add("co");
searcher.PropertiesToLoad.Add("company");
searcher.PropertiesToLoad.Add("mail");
searcher.Filter = String.Format("(SAMAccountName={0})", samAccountName);
searcher.SearchScope = SearchScope.Subtree;
searcher.PageSize = 1000;
SearchResult result = searcher.FindOne();
ResultPropertyCollection resultPropColl = result.Properties;
Object memberColl = resultPropColl["member"];
using (DirectoryEntry memberEntry = new DirectoryEntry("LDAP://" + memberColl, ldapu, ldapp))
{
try
{
System.DirectoryServices.PropertyCollection userprops = memberEntry.Properties;
object obVal = userprops["SAMAccountName"].Value;
예외는 무엇입니까? –
서버가 작동하지 않습니다. COMException. –
속성을 확인하십시오. SAMAccountName은 sAMAccountName이어야합니다 (링크 : http://msdn.microsoft.com/en-us/library/windows/desktop/ms679635(v=vs.85).aspx) – jwillmer