coffeescript의 매개 변수 내부

Question

coffeescript가 그 메소드를 다른 매개 변수로 사용하지 않는다고 말할 수 있습니까?

 
$('#id-calendar').fullCalendar 
    aspectRatio: 0.5 
    editable: true 
    droppable: true 
    defaultView: 'agendaWeek' 
    slotMinutes: 120 
    minTime: 8 
    maxTime: 20 
    firstDay: startDate() 
    drop = (date, allDay, jsEvent, ui) -> 
    console.log(date) 
    console.log(allDay) 
    console.log(jsEvent) 
    console.log(ui) 
    originalEventObject = $(this).data('eventObject') 
    copiedEventObject = $.extend({}, originalEventObject) 
    copiedEventObject.start = date 
    copiedEventObject.allDay = allDay 
    $('#id-calendar').fullCalendar('renderEvent', copiedEventObject, true) 
    $(this).remove() 
    return true 

출력 : 그것은

drop: (date, allDay, jsEvent, ui) -> 

하지 drop =되어야

 

var drop; 

$(document).ready(function() { 
    var startDate; 
    startDate = function() { 
    var day, today; 
    today = new Date(); 
    day = today.getDay(); 
    switch (day - 2) { 
     case -1: 
     return 6; 
     case -2: 
     return 5; 
     default: 
     return day - 2; 
    } 
    }; 
    return $('#external-events div.external-event').each(function() { 
    var eventObject; 
    eventObject = { 
     title: $.trim($(this).text()) 
    }; 
    $(this).data('eventObject', eventObject); 
    return $(this).draggable({ 
     zIndex: 999, 
     evert: true, 
     revertDuration: 0 
    }); 
    }); 
}); 

$('#id-calendar').fullCalendar({ 
    aspectRatio: 0.5, 
    editable: true, 
    droppable: true, 
    defaultView: 'agendaWeek', 
    slotMinutes: 120, 
    minTime: 8, 
    maxTime: 20, 
    firstDay: startDate() 
}, drop = function(date, allDay, jsEvent, ui) { === BUG 
    var copiedEventObject, originalEventObject; 
    console.log(date); 
    console.log(allDay); 
    console.log(jsEvent); 
    console.log(ui); 
    originalEventObject = $(this).data('eventObject'); 
    copiedEventObject = $.extend({}, originalEventObject); 
    copiedEventObject.start = date; 
    copiedEventObject.allDay = allDay; 
    $('#id-calendar').fullCalendar('renderEvent', copiedEventObject, true); 
    $(this).remove(); 
    return true; 
}); 

Answer 1

.