다음 표가 있습니다.SQL 개수 구별 행
Date Direction Market Time
10/17/2016 SB GRUJFK 22:05:00
10/18/2016 SB GRUJFK 22:05:00
10/19/2016 SB GRUJFK 22:05:00
10/20/2016 SB GRUJFK 22:05:00
10/21/2016 SB GRUJFK 22:05:00
10/23/2016 SB GRUJFK 23:20:00
10/23/2016 SB GRUJFK 22:30:00
10/24/2016 SB GRUJFK 22:30:00
10/25/2016 SB GRUJFK 22:30:00
10/26/2016 SB GRUJFK 22:30:00
10/27/2016 SB GRUJFK 22:30:00
10/28/2016 SB GRUJFK 22:30:00
I이 경우에만 10/23 너무
Date Direction Market Time Count
10/17/2016 SB GRUJFK 22:05:00 1
10/18/2016 SB GRUJFK 22:05:00 1
10/19/2016 SB GRUJFK 22:05:00 1
10/20/2016 SB GRUJFK 22:05:00 1
10/21/2016 SB GRUJFK 22:05:00 1
10/23/2016 SB GRUJFK 23:20:00 1
10/23/2016 SB GRUJFK 22:30:00 2
10/23/2016 SB GRUJFK 23:30:00 3
10/25/2016 SB GRUJFK 22:30:00 1
10/26/2016 SB GRUJFK 22:30:00 1
10/27/2016 SB GRUJFK 22:30:00 1
10/28/2016 SB GRUJFK 22:30:00 1
다른 열에 구별 행을 계산하지만 (1..N에서) 반복 행 번호를 순차적으로 할당하고자
/2016에는 3 가지 값이 있습니다. 그래서
Date Direction Market Time Count
10/17/2016 SB GRUJFK 22:05:00 1
10/18/2016 SB GRUJFK 22:05:00 1
10/19/2016 SB GRUJFK 22:05:00 1
10/20/2016 SB GRUJFK 22:05:00 1
10/21/2016 SB GRUJFK 22:05:00 1
10/23/2016 SB GRUJFK 23:20:00 3
10/23/2016 SB GRUJFK 22:30:00 3
10/23/2016 SB GRUJFK 23:30:00 3
10/25/2016 SB GRUJFK 22:30:00 1
10/26/2016 SB GRUJFK 22:30:00 1
10/27/2016 SB GRUJFK 22:30:00 1
10/28/2016 SB GRUJFK 22:30:00 1
모든 아이디어를 얻을 등, 첫 번째 항목, 두 번째 2에 1을 할당
나는 다음과 같은select
departureDate,
DIRECTION, LEG, SCHD_LEG_DEP_TM, count(SCHD_LEG_DEP_TM) over (partition by departureDate)
from table3mirs mirs
INNER JOIN sys_calendar.calendar
ON calendar_date = mirs.departureDate
where leg='GRUJFK'
group by 1,2,3,4
하지만 시도? 당신의 도움을 주셔서 감사합니다!
.. 보인다. http://dba.stackexchange.com/questions/89031/using-distinct-in-window-function-with-over – vercelli