1
와 드롭 다운 옵션 값을 지정하려면 :어떻게 내 스크립트에 다음과 같이 배열을 배열
var TypeList = {
'One': ["Any", "Abigail", "Adam", "Jake", "Michael"],
'Two': ["Any", "Gavin", "Amanda", "Donna", "Irene"],
'Three': ["Any", "Sarah", "Nicholas", "Ellison", "Cornish", "Neil"],
'Four': ["Any", "Rebecca", "Sophie", "Yvonne", "William", "Hill"]
}
그러나 나는이 같은 드롭 다운 옵션에서 값을 추가 할 :
Option One
Value: Any Text: Any
Value: 1 Text: Abigail
Value: 3 Text: Adam
Value: 4 Text: Jake
Value: 5 Text: Michael
Option Two
Value: Any Text: Any
Value: 6 Text: Gavin
Value: 7 Text: Amanda
Value: 8 Text: Donna
Value: 9 Text: Irene
Option Three
Value: Any Text: Any
Value: 10 Text: Sarah
Value: 11 Text: Nicholas
Value: 12 Text: Ellison
Value: 13 Text: Cornish
Value: 14 Text: Neil
Option Four
Value: Any Text: Any
Value: 15 Text: Rebecca
Value: 16 Text: Sophie
Value: 17 Text: Yvonne
Value: 18 Text: William
Value: 19 Text: Hill
내 현재 코드 :
<!doctype html>
<html>
<head>
<title>Custom Styled Selectbox</title>
<link rel="stylesheet" href="http://www.roblaplaca.com/docs/custom-selectbox/css/customSelectBox.css" />
</head>
<body class="noJS">
<script type="text/javascript">
try{Typekit.load();}catch(e){}
var bodyTag = document.getElementsByTagName("body")[0];
bodyTag.className = bodyTag.className.replace("noJS", "hasJS");
</script>
<div class="grid-system clearfix">
<div class="row">
<div class="col span-9">
<div class="example clearfix">
<select class="custom interactive" id="properties">
<option value="One" selected>One</option>
<option value="Two">Two</option>
<option value="Three">Three</option>
<option value="Four">Four</option>
</select>
<select class="custom interactive" id="TypeList">
<option selected>One</option>
<option>Two</option>
<option>Three</option>
<option>Four</option>
</select>
</div>
</div>
</div>
</div>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.0/jquery.min.js"></script>
<script src="http://github.com/vitch/jScrollPane/raw/master/script/jquery.jscrollpane.js"></script>
<script src="http://www.roblaplaca.com/docs/custom-selectbox/js/SelectBox.js"></script>
<script type="text/javascript">
$(function() {
window.prettyPrint && prettyPrint()
/*
This is how initialization normally looks.
Typically it's just $("select.custom"), but to make this example more clear
I'm breaking from the pattern and excluding interactive
*/
var sb, sb2;
$("select.custom").not(".interactive").each(function() {
sb = new SelectBox({
selectbox: $(this),
height: 150,
width: 200
});
});
/*
Adding some extra functionality for "interactive" selects
*/
var TypeList = {
'One': ["Any", "Abigail", "Adam", "Jake", "Michael"],
'Two': ["Any", "Gavin", "Amanda", "Donna", "Irene"],
'Three': ["Any", "Sarah", "Nicholas", "Ellison", "Cornish", "Neil"],
'Four': ["Any", "Rebecca", "Sophie", "Yvonne", "William", "Hill"]
}
var defaultSelectboxSettings = {
height: 150,
width: 150
};
var country_SB = null,
city_SB = null;
$("select.interactive").each(function() {
if ($(this).attr("id") == "properties") {
country_SB = new SelectBox($.extend(defaultSelectboxSettings, {
selectbox: $(this),
changeCallback: function(val) {
if (TypeList[val]) {
city_SB.enable();
updateCities(val);
}
if (val == "selectone") {
city_SB.disable();
}
}
}));
} else if ($(this).attr("id") === "TypeList") {
city_SB = new SelectBox($.extend(defaultSelectboxSettings, {
selectbox: $(this)
}));
}
});
updateCities($("#properties").val());
if ($("#properties").val() == "selectone") {
//city_SB.disable();
}
function updateCities(val) {
var $select = $("select#TypeList"),
html = "";
for (var i = 0; i < TypeList[val].length; i++) {
html += '<option>' + TypeList[val][i] + '</option>';
}
$select.html(html);
// HACK: chrome is too fast?
setTimeout(function() {
city_SB.sync();
}, 1);
}
});
</script>
</body>
</html>
내 코드 참조 링크 Rob La Placa
아이디어 나 제안이 있으십니까? 감사.
<select id="one"></select>
<select id="two"></select>
<select id="three"></select>
<select id="four"></select>
그냥 기본적인 예입니다,하지만 원하는 HTML을 생성합니다 :
var TypeList = {
'One': ["Any", "Abigail", "Adam", "Jake", "Michael"],
'Two': ["Any", "Gavin", "Amanda", "Donna", "Irene"],
'Three': ["Any", "Sarah", "Nicholas", "Ellison", "Cornish", "Neil"],
'Four': ["Any", "Rebecca", "Sophie", "Yvonne", "William", "Hill"]
};
var counter = 1;
addFromArray(TypeList.One, "one");
addFromArray(TypeList.Two, "two");
addFromArray(TypeList.Three, "three");
addFromArray(TypeList.Four, "four");
function addFromArray(arrayItems, dropdown)
{
for(var i = 0; i < arrayItems.length; i++)
{
$("#" + dropdown).append("<option value='" + (i===0?"Any":counter) + "'>" + arrayItems[i] + "</option>");
if (i!==0)
counter++;
}
}
마크 업 :
JQuery와 :
FYI, TypeList는 값이 배열 인 목적이다. – Andy
@Andy 좋아,하지만 내가 말하는 출력을 생성하는 방법. – Manan