zf2에서 외래 키가있는 테이블에서 데이터를 가져 오는 방법은 무엇입니까?

Question

도와주세요! 'table'의 식당 가져 오기 필드가 필요합니다 - restaurant_longitude. tableGateway 또는 Zend \ Db \를 사용하여 zf2에서이 작업을 수행하는 방법 테이블 '외식업'에 외래 키가있는 테이블 ('user_favorite' 예를 -restaurant_id.For : 표현에 복귀 필드

SELECT restaurant_longitude from restaurant,user_favorite where user_favorite.restaurant_id = restaurant.restaurant_id 

내 명확하게 SQL 문을

select restaurant_longitude,restaurant_latitude from user_favorite join restaurant on user_favorite.restaurant_id = restaurant.restaurant_id where user_favorite.display_name = 'admin' 

user_favorite.sql; 컨트롤러

CREATE TABLE IF NOT EXISTS `user_favorite` (
    `user_favorite_id` int(11) NOT NULL AUTO_INCREMENT, 
    `display_name` varchar(50) CHARACTER SET utf8 NOT NULL, 
    `restaurant_id` int(11) DEFAULT NULL, 
    `attraction_id` int(11) DEFAULT NULL, 
    `user_favorite_timestamp` date NOT NULL, 
    PRIMARY KEY (`user_favorite_id`), 
    KEY `display_name` (`display_name`), 
    KEY `restaurant_id` (`restaurant_id`), 
    KEY `attraction_id` (`attraction_id`) 
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=42 ; 

ALTER TABLE `user_favorite` 
    ADD CONSTRAINT `user_favorite_ibfk_1` FOREIGN KEY (`display_name`) REFERENCES `user` (`display_name`), 
    ADD CONSTRAINT `user_favorite_ibfk_3` FOREIGN KEY (`attraction_id`) REFERENCES `attraction` (`attraction_id`), 
    ADD CONSTRAINT `user_favorite_ibfk_4` FOREIGN KEY (`restaurant_id`) REFERENCES `restaurant` (`restaurant_id`); 

restaurant.sql

CREATE TABLE IF NOT EXISTS `restaurant` (
    `restaurant_id` int(11) NOT NULL AUTO_INCREMENT COMMENT 'Уникальный идентификатор ресторана', 
    `restaurant_id_name` varchar(100) NOT NULL COMMENT 'Идентификатор ресторана для маршутизации', 
    `restaurant_name` varchar(100) NOT NULL COMMENT 'Имя ресторана', 
    `restaurant_mode` varchar(100) NOT NULL COMMENT 'Тип ресторана', 
    `restaurant_description` varchar(1000) NOT NULL COMMENT 'Описание ресторана', 
    `restaurant_thumbnail` varchar(100) NOT NULL COMMENT 'Главный рисунок ресторана', 
    `restaurant_image_1` varchar(100) NOT NULL, 
    `restaurant_image_2` varchar(100) NOT NULL, 
    `restaurant_image_3` varchar(100) NOT NULL, 
    `restaurant_features` varchar(200) NOT NULL COMMENT 'Возможности ресторана', 
    `restaurant_dj` varchar(20) NOT NULL, 
    `restaurant_wifi` varchar(20) NOT NULL, 
    `restaurant_karaoke` int(5) NOT NULL, 
    `restaurant_kalian` int(5) NOT NULL, 
    `restaurant_chill_out` int(5) NOT NULL, 
    `restaurant_sigarette_room` int(5) NOT NULL, 
    `restaurant_live_music` int(5) NOT NULL, 
    `restaurant_veranda` int(5) NOT NULL, 
    PRIMARY KEY (`restaurant_id`), 
    KEY `restaurant_id_name` (`restaurant_id_name`) 
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COMMENT='Таблица для описания ресторанов в городе Ялта' AUTO_INCREMENT=95 ; 

에 UserFavoriteTable.php

public function getFavoriteByUsername($display_name){ 

     $resultSet = $this->tableGateway->select(function (Select $select) use($display_name){ 
      $select->where('user_favorite.display_name = ' . $display_name) 
       ->join('restaurant', 'user_favorite.restaurant_id = restaurant.restaurant_id',array('restaurant_longitude')); 
     }); 
     return $resultSet; 
    } 

//username from route array in module.config.php 
$display_name = (string)$this->params()->fromRoute('username',''); 
$favorite = $this->getFavoriteTable()->getFavoriteByUsername($display_name); 
$view->setVariable('favorite',$favorite); 

,536,913,632 10

하지만 그렇지 좋은 반환에만 작동 널 ( favorite.phml

<? foreach($favorite as $fav): {?> 
          <? echo var_dump($fav->restaurant_longitude); ?> 
         <? }endforeach; ?> 

Answer 1

편집 : 좋아, 분명히 방금 표시 이름으로 이동하여이 사용자 테이블에 가입 할 필요가 없습니다. 이것이 어떻게 완료되었는지입니다.

public function getFavoriteByUsername($username){ 
    $resultSet = $this->tableGateway->select(function (Select $select) use($username){ // Here's how you can pass params to a select statement! 
    $select->where('display_name = ' . $username) 
     ->join('restaurant', 'user_favorite.restaurant_id = restaurant.restaurant_id',array('restaurant_longitude', 'restaurant_latitude'); 
    }); 
return $resultSet; 
}