이 mysql 쿼리를 수정하여 승률을 표시 하시겠습니까?

Question

아래에이 쿼리 (각 플레이어는 게임의 다른 수를 해왔다 수 있으므로)

+---------+-----------+ 
| member | Wins | 
+---------+-----------+ 
| Player 1|  4  | 
| Player 2|  3  | 
| Player 3|  3  | 
+---------+-------------+ 

는 내가 보여주고 싶은 데이터가 더 유용하게하려면 :

SELECT member, count(*) Wins 
FROM (SELECT player2_name as member from results 
WHERE player1_id = 2 AND player1_result = 'W' AND community_id = 16 
UNION ALL SELECT player1_name FROM results WHERE player2_id = 2 
AND player2_result = 'W' AND community_id = 16) AS T 
group by member ORDER BY Wins DESC 

같은 결과를 생성합니다 추가 열 '승리 비율'.

-> 이것은 각 플레이어가 플레이 한 게임 수에 기반합니다.

+---------+-----------+---------------+---------+ | member | Wins | Games Played | Win % | +---------+-----------+---------------+---------+ | Player 1| 4 | 8 | 0.50 | | Player 2| 3 | 3 | 1.00 | | Player 3| 3 | 5 | 0.60 | +---------+-----------+---------------+---------+

내가 바라고있다 - %를 출력하는 MySQL을 직접 할 수없는 경우 다음 진수 나는 아래와 같은 출력을 생성하기 위해 기존 쿼리를 수정할 수있는 방법 0.76

즉, 잘 될 것입니다

SELECT GamesPlayed FROM (SELECT player1_name as member from results 
WHERE player1_id = 2 AND community_id = 16 
UNION ALL SELECT player2_name FROM results WHERE player2_id = 2 
AND community_id = 16) AS GP 

다음 행 1 : 단지의 라인을 따라 뭔가를 추가하는

SELECT member, count(*) Wins, round(sum(wins/GamesPlayed(1),2) WinPercentage 

,

하지만 그게 얼마나 힘든 일인지 잘 모르겠다.

최신 테스트 데이터 :이 같은

Answer 1

뭔가?

업데이트 쿼리

SELECT 
    T.member 
    , count(*) Wins 
    , total.gamesPlayed 
    , count(*)/total.gamesPlayed as winPercentage 
FROM 
    (
     SELECT 
      player2_name as member 
     from results 
     WHERE 
      player1_id = 2 
      AND player1_result = 'W' 
      AND community_id = 16 
     UNION ALL 
     SELECT 
      player1_name 
     FROM results 
      WHERE player2_id = 2 
      AND player2_result = 'W' 
      AND community_id = 16 
    ) AS T 
    , (
      select 
       u.member 
       , sum(u.gamesPlayed) as gamesPlayed 
      from 
       (
        select 
         player2_name as member 
         , count(*) gamesPlayed 
        from results 
        where 
         player1_id = 2 
         AND community_id = 16 
        group by player2_name 
        union 
        select 
         player1_name as member 
         , count(*) gamesPlayed 
        from results 
        where 
         player2_id = 2 
         AND community_id = 16 
        group by player2_name 
       ) as u /* union of two */ 
      group by member 
    ) as total 
where 
    T.member = total.member 
group by T.member 
ORDER BY Wins DESC