,이 배열을 처리하여이 결과를 얻으려면 어떻게해야합니까? 나는이 배열을
array (size=6)
0 =>
array (size=6)
'id' => string '2' (length=1)
'member_ext' => string '1' (length=1)
'queue_id' => string '1' (length=1)
'LastUpdate' => string '2013-10-24' (length=10)
'member_name' => string 'John Smith' (length=10)
'queue_name' => string 'queue 1' (length=7)
1 =>
array (size=6)
'id' => string '3' (length=1)
'member_ext' => string '2' (length=1)
'queue_id' => string '1' (length=1)
'LastUpdate' => string '2013-10-24' (length=10)
'member_name' => string 'Jose Jones' (length=10)
'queue_name' => string 'queue 1' (length=7)
2 =>
array (size=6)
'id' => string '5' (length=1)
'member_ext' => string '1' (length=1)
'queue_id' => string '1' (length=1)
'LastUpdate' => string '2013-10-24' (length=10)
'member_name' => string 'John Smith' (length=10)
'queue_name' => string 'queue 1' (length=7)
3 =>
array (size=6)
'id' => string '4' (length=1)
'member_ext' => string '3' (length=1)
'queue_id' => string '2' (length=1)
'LastUpdate' => string '2013-10-24' (length=10)
'member_name' => string 'Mary Chase' (length=10)
'queue_name' => string 'queue 2' (length=7)
4 =>
array (size=6)
'id' => string '7' (length=1)
'member_ext' => string '3' (length=1)
'queue_id' => string '3' (length=1)
'LastUpdate' => string '2013-10-24' (length=10)
'member_name' => string 'Mary Chase' (length=10)
'queue_name' => string 'queue 3' (length=7)
5 =>
array (size=6)
'id' => string '6' (length=1)
'member_ext' => string '4' (length=1)
'queue_id' => string '4' (length=1)
'LastUpdate' => string '2013-10-24' (length=10)
'member_name' => string 'Fred Allen' (length=10)
'queue_name' => string 'queue 4' (length=7)
어떻게이 같은 HTML 테이블에 그걸 얻기 위해 PHP를 사용할 수 있습니까? "로그인 됨"이라는 의미는 배열에서 특정 큐에 로그인되어있는 채 벌칙으로 검색된 것으로, 로그 아웃된다는 의미는 해당 기술 큐가 특정 큐에없는 것을 의미합니다.
| techs | queue 1 | queue 2 | queue 3 | queue 4 | queue 5 |
------------------------------------------------------------------------------
|John Smith | logged in | logged in | logged out | logged out | logged out |
|Jose Jones | logged in | logged out | logged out | logged out | logged out |
|Mary Case | logged out | logged out | logged in | logged out | logged out |
|Fred Allen | logged out | logged out | logged out | logged in | logged out |
편집 - 이것은 내가 지금까지 해왔 던 것입니다.
<?php
try {
$username = "admin";
//$password = "TrojanF32";
$dbh = new PDO('mysql:host=localhost;dbname=test', $username);
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
echo "connected<p>";
} catch(PDOException $e) {
echo 'ERROR: ' . $e->getMessage();
}
$sth = $dbh->prepare("SELECT DISTINCT queue_name
FROM `log`
WHERE LastUpdate = '2013-10-24'
ORDER BY queue_name ASC
");
$sth->execute();
$sql1 = $sth->fetchAll(PDO::FETCH_ASSOC);
$sth = $dbh->prepare("SELECT *
FROM `log`
WHERE LastUpdate = '2013-10-24'
ORDER BY queue_name ASC
");
$sth->execute();
$sql2 =$sth->fetchAll(PDO::FETCH_ASSOC);
?><div class="container"><?php
echo "<table border=1>";
echo "<tr>";
echo "<td>" . "Technician" . "</td>";
foreach($sql1 as $header){
echo "<td>" . $header['queue_name'] . "</td>";
}
echo "</tr>";
foreach($sql2 as $queue){
echo "<td>" . $queue['member_name'] . "</td>";
//echo "<td>";
foreach($queue as $que){
if($queue['queue_id'] == '1'){
echo "<td>" . "logged in" . "</td>";
}else{
echo "<td>" . "logged out" . "</td>";
}
if($queue['queue_id'] == '2'){
echo "<td>" . "logged in" . "</td>";
}else{
echo "<td>" . "logged out" . "</td>";
}
if($queue['queue_id'] == '3'){
echo "<td>" . "logged in" . "</td>";
}else{
echo "<td>" . "logged out" . "</td>";
}
if($queue['queue_id'] == '4'){
echo "<td>" . "logged in" . "</td>";
}else{
echo "<td>" . "logged out" . "</td>";
}
if($queue['queue_id'] == '5'){
echo "<td>" . "logged in" . "</td>";
}else{
echo "<td>" . "logged out" . "</td>";
}
echo "</tr>";
}
}
echo "<pre>";
var_dump($sql2);
echo "</pre>";
?>
</table>
</div>
이미 시도한 코드를 표시하십시오. –
무엇을 시도 했습니까? 현재 코드는 어디에 있습니까? 사용자가 로그인/로그 아웃했는지 어떻게 알 수 있습니까? – Lepidosteus
수정 된, 미안, 좌절감이 현재 매우 높습니다. 분노와 절망에 맞게 게시했습니다. –