PHP 스크립트 + MySQL 한 행만 반환

Question

PHP 페이지가 한 쌍을 반환하는 대신 한 행만 반환하는 문제가 있습니다. 테이블에서 여러 행을 멋지게 반환해야하지만 그렇지 않습니다. 나타나는 행을 삭제하면 다음 행 (여전히 하나)이 표시됩니다.

업데이트 : 죄송합니다. 어떤 MySQL 쿼리에 대한 설명이 없습니다. 그것은

PS "WHERE 활성 = 2 ... 사용자 SELECT * FROM"에 관한 것입니다 : 내가해야 하지 사용 MySQL과 대신 PDO 또는 MySQLi를 알고 있지만 곧이를 변경할 수 있습니다.

 <? $result = mysql_query("SELECT * FROM school WHERE schoolid = '$schoolvanleerling'"); while($row = mysql_fetch_array($result)){ 
    echo $schoolnaam = $row['schoolnaam']; 

    } ?>. 

    </p><br> 
    <h3>Actieve tutors</h3> 
       <table class="demotable" border="0" cellspacing="0" cellpadding="0"> 
           <tr> 
            <th>Naam tutor</th> 
            <th>Klas tutor</th> 
            <th>Vakken tutor</th> 
            <th>Rating tutor</th> 
            <th>Cijfer tutor</th> 
            <th>Acties</th> 
           </tr> 
<? $result = mysql_query("SELECT * FROM users WHERE active = '2' AND bijles_school = '$schoolvanleerling' ORDER BY name ASC"); while($row = mysql_fetch_array($result)){ 
?> 

            <tr> 
             <td><a href="profiel.php?id=<? echo $row['id'];?>"><? echo $row['name'];?></a></td> 
             <td><? $result = mysql_query("SELECT * FROM klas WHERE id = '$row[klas]'"); while($rowa = mysql_fetch_array($result)){ ?><? echo $rowa['naam'];?><? }?></td> 
             <td> <? $bijlesvakkenn = explode(",", $row['bijles_tutor']); 
    foreach ($bijlesvakkenn as $value) { 
    ?> 
    <? $result = mysql_query("SELECT * FROM vakken WHERE id = '$value' ORDER BY naam ASC"); while($rowvak = mysql_fetch_array($result)){ 
    echo $rowvak['naam'];?><br><? } } ?></td> 
             <td><? // echo getRating($row['id']); ?></td> 
             <td>nog geen cijfer beschikbaar</td> 
             <td>- Deactiveer Tutor<br>- <a href="mailto:<? echo $row['email'];?>">Contact opnemen</a></td> 
            </tr> 

            <? } ?> 
           </table> 
    <br><br> 
    <h3>Niet goedgekeurde tutors</h3> 
        <table class="demotable" border="0" cellspacing="0" cellpadding="0"> 
            <tr> 
             <th>Naam tutor</th> 
             <th>Klas tutor</th> 
             <th>Vakken tutor</th> 
             <th>Rating tutor</th> 
             <th>Cijfer tutor</th> 
             <th>Acties</th> 
            </tr> 
    <? $result = mysql_query("SELECT * FROM users WHERE active = '1' AND bijles_school = '$schoolvanleerling' ORDER BY 

name ASC"); while($row = mysql_fetch_array($result)){ 
?> 
           <tr> 
            <td><? echo $row['name'];?></td> 
            <td><? $result = mysql_query("SELECT * FROM klas WHERE id = '$row[klas]'"); while($rowa = mysql_fetch_array($result)){ ?><? echo $rowa['naam'];?><? }?></td> 
            <td> <? $bijlesvakkenn = explode(",", $row['bijles_tutor']); 
foreach ($bijlesvakkenn as $value) { 

?> 
<? $result = mysql_query("SELECT * FROM vakken WHERE id = '$value' ORDER BY naam ASC"); while($row = mysql_fetch_array($result)){ 
echo $row['naam'];?><br><? } } ?></td> 
            <td><? echo getRating($row['id']); ?></td> 
            <td>8</td> 
            <td>- Deactiveer Tutor<br>- Contact opnemen</td> 
           </tr> 

           <? } ?> 
          </table> 
<?php } ?> 

업데이트] WORKING 코드 : 변화는 두 번 이상

<? $resultschool = mysql_query("SELECT * FROM school WHERE schoolid = '$schoolvanleerling'"); while($rowschool = mysql_fetch_array($resultschool)){ 
echo $schoolnaam = $rowschool['schoolnaam']; 
} ?>. 
</p><br> 
<h3>Actieve tutors</h3> 
       <table class="demotable" border="0" cellspacing="0" cellpadding="0"> 
           <tr> 
            <th>Naam tutor</th> 
            <th>Klas tutor</th> 
            <th>Vakken tutor</th> 
            <th>Rating tutor</th> 
            <th>Cijfer tutor</th> 
            <th>Acties</th> 
           </tr> 
<? $result = mysql_query("SELECT * FROM users WHERE active = 2 AND bijles_school = '$schoolvanleerling' ORDER BY name ASC"); while($row = mysql_fetch_array($result)){ 
?> 
           <tr> 
            <td><a href="profiel.php?id=<? echo $row['id'];?>"><? echo $row['name'];?></a></td> 
            <td><? $resulta = mysql_query("SELECT * FROM klas WHERE id = '$row[klas]'"); while($rowa = mysql_fetch_array($resulta)){ ?><? echo $rowa['naam'];?><? }?></td> 
            <td> <? $bijlesvakkenn = explode(",", $row['bijles_tutor']); 
foreach ($bijlesvakkenn as $value) { 

?> 
<? $resultvak = mysql_query("SELECT * FROM vakken WHERE id = '$value' ORDER BY naam ASC"); while($rowvak = mysql_fetch_array($resultvak)){ 
echo $rowvak['naam'];?><br><? } } ?></td> 
            <td><? // echo getRating($row['id']); ?></td> 
            <td>nog geen cijfer beschikbaar</td> 
            <td>- <a href="mijnprofiel.php?do=manageschool&action=deactivatetutor&id=<? echo $row['id'];?>">Deactiveer Tutor</a><br>- <a href="mailto:<? echo $row['email'];?>">Contact opnemen</a></td> 
           </tr> 

           <? } ?> 

당신은 그냥 코드에서이 코드를 교체

Answer 1

내가 그 작업

생각 나는 $ 결과를 사용하여 더 이상이야 없다는 것이다

<? $resultschool = mysql_query("SELECT * FROM school WHERE schoolid = '$schoolvanleerling'"); 

    while($rowschool = mysql_fetch_array($resultschool)) 
    { 
    $schoolnaam = $rowschool['schoolnaam']; 
    } ?> 
    </p><br> 
    <h3>Actieve tutors</h3> 
      <table class="demotable" border="0" cellspacing="0" cellpadding="0"> 
          <tr> 
           <th>Naam tutor</th> 
           <th>Klas tutor</th> 
           <th>Vakken tutor</th> 
           <th>Rating tutor</th> 
           <th>Cijfer tutor</th> 
           <th>Acties</th> 
          </tr> 
     <? $result = mysql_query("SELECT * FROM users WHERE active = 2 AND bijles_school = '$schoolvanleerling' ORDER BY name ASC"); 

    while($row = mysql_fetch_array($result)){ 
     ?> 
          <tr> 
           <td><a href="profiel.php?id=<? echo $row['id'];?>"><?   echo $row['name'];?></a></td> 
           <td><? $resulta = mysql_query("SELECT * FROM klas WHERE id = '$row[klas]'"); 
           while($rowa = mysql_fetch_array($resulta)){ 
            echo $rowa['naam']; 
            }?></td> 
           <td> <? $bijlesvakkenn = explode(",", $row['bijles_tutor']); 
           foreach ($bijlesvakkenn as $value) { 
                    $resultvak = mysql_query("SELECT * FROM vakken WHERE id = '$value' ORDER BY naam ASC"); 
                    while($rowvak = mysql_fetch_array($resultvak)){ 
                     echo $rowvak['naam']."<br>"; 
                     } 
                    } ?></td> 
           <td><? // echo getRating($row['id']); ?></td> 
           <td>nog geen cijfer beschikbaar</td> 
           <td><a href="mijnprofiel.php?do=manageschool&action=deactivatetutor&id=<? echo $row['id'];?>">Deactiveer Tutor</a><br>- <a href="mailto:<? echo $row['email'];?>">Contact opnemen</a></td> 
          </tr> 

          <? 
         } ?>