MySQL WorkBench의 오류 코드 1022

이 테이블을 만들려고하지만 cadastro_fornecedor 테이블을 만들 때 오류 1022가 발생합니다. 이 문제를 해결하기 위해 어디서부터 시작해야할지 모르겠으므로 어떠한 종류의 도움도 환영합니다.MySQL WorkBench의 오류 코드 1022

SET @[email protected]@UNIQUE_CHECKS, UNIQUE_CHECKS=0; 
SET @[email protected]@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; 
SET @[email protected]@SQL_MODE, SQL_MODE='TRADITIONAL,ALLOW_INVALID_DATES'; 

-- ----------------------------------------------------- 
-- Schema mydb 
-- ----------------------------------------------------- 
CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET utf8 COLLATE utf8_general_ci ; 
USE `mydb` ; 

-- ----------------------------------------------------- 
-- Table `mydb`.`administrador` 
-- ----------------------------------------------------- 
CREATE TABLE IF NOT EXISTS `mydb`.`administrador` (
    `id_administrador` INT NOT NULL, 
    `nome` VARCHAR(45) NULL, 
    `senha` VARCHAR(45) NULL, 
    `CPF` INT NULL, 
    `endereço` VARCHAR(45) NULL, 
    `data_nascimento` DATE NULL, 
    PRIMARY KEY (`id_administrador`)) 
ENGINE = InnoDB; 


-- ----------------------------------------------------- 
-- Table `mydb`.`cadastro_usuario` 
-- ----------------------------------------------------- 
CREATE TABLE IF NOT EXISTS `mydb`.`cadastro_usuario` (
    `id_cadastro` INT NOT NULL AUTO_INCREMENT, 
    `data_cadastro` DATETIME NOT NULL, 
    `id_administrador` INT NULL, 
    `usuario` INT NULL, 
    PRIMARY KEY (`id_cadastro`), 
    INDEX `id_administrador_idx` (`id_administrador` ASC), 
    INDEX `matricula_idx` (`usuario` ASC), 
    CONSTRAINT `id_administrador` 
    FOREIGN KEY (`id_administrador`) 
    REFERENCES `mydb`.`administrador` (`id_administrador`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION, 
    CONSTRAINT `matricula` 
    FOREIGN KEY (`usuario`) 
    REFERENCES `mydb`.`usuario_cadastrado` (`matricula`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION) 
ENGINE = InnoDB; 


-- ----------------------------------------------------- 
-- Table `mydb`.`usuario_cadastrado` 
-- ----------------------------------------------------- 
CREATE TABLE IF NOT EXISTS `mydb`.`usuario_cadastrado` (
    `matricula` INT NOT NULL, 
    `nome` VARCHAR(45) NULL, 
    `endereco` VARCHAR(45) NULL, 
    `senha` VARCHAR(45) NULL, 
    `nacionalidade` VARCHAR(45) NULL DEFAULT 'brasileiro', 
    `naturalidade` VARCHAR(45) NULL, 
    `sexo` CHAR NULL, 
    `data_nascimento` DATE NULL, 
    `CPF` INT NULL, 
    `nome_pai` VARCHAR(45) NULL, 
    `nome_mae` VARCHAR(45) NULL, 
    `telefone_celular` VARCHAR(15) NULL, 
    `telefone_fixo` VARCHAR(15) NULL, 
    `id_cadastro` INT NULL, 
    PRIMARY KEY (`matricula`), 
    INDEX `id_cadastro_idx` (`id_cadastro` ASC), 
    CONSTRAINT `id_cadastro` 
    FOREIGN KEY (`id_cadastro`) 
    REFERENCES `mydb`.`cadastro_usuario` (`id_cadastro`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION) 
ENGINE = InnoDB; 


-- ----------------------------------------------------- 
-- Table `mydb`.`obra` 
-- ----------------------------------------------------- 
CREATE TABLE IF NOT EXISTS `mydb`.`obra` (
    `ISBN` VARCHAR(20) NOT NULL, 
    `titulo` VARCHAR(45) NULL, 
    `autor` VARCHAR(45) NULL, 
    `ano` YEAR NULL, 
    `editora` VARCHAR(45) NULL, 
    `categoria` VARCHAR(45) NULL, 
    `assunto` VARCHAR(45) NULL, 
    `descricao` VARCHAR(45) NULL, 
    PRIMARY KEY (`ISBN`)) 
ENGINE = InnoDB; 


-- ----------------------------------------------------- 
-- Table `mydb`.`fornecedores` 
-- ----------------------------------------------------- 
CREATE TABLE IF NOT EXISTS `mydb`.`fornecedores` (
    `CNPJ` VARCHAR(45) NOT NULL, 
    `nome` VARCHAR(45) NOT NULL, 
    `endereco` VARCHAR(45) NULL, 
    `telefone` VARCHAR(45) NULL, 
    PRIMARY KEY (`CNPJ`)) 
ENGINE = InnoDB; 


-- ----------------------------------------------------- 
-- Table `mydb`.`exemplar` 
-- ----------------------------------------------------- 
CREATE TABLE IF NOT EXISTS `mydb`.`exemplar` (
    `codigo_exemplar` INT NOT NULL, 
    `data_aquisicao` DATE NULL, 
    `edição` INT NULL, 
    `volume` INT NULL, 
    `paginas` INT NULL, 
    `ISBN` VARCHAR(20) NULL, 
    `CNPJ` VARCHAR(45) NULL, 
    PRIMARY KEY (`codigo_exemplar`), 
    INDEX `ISBN_idx` (`ISBN` ASC), 
    INDEX `CNPJ_idx` (`CNPJ` ASC), 
    CONSTRAINT `ISBN` 
    FOREIGN KEY (`ISBN`) 
    REFERENCES `mydb`.`obra` (`ISBN`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION, 
    CONSTRAINT `CNPJ` 
    FOREIGN KEY (`CNPJ`) 
    REFERENCES `mydb`.`fornecedores` (`CNPJ`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION) 
ENGINE = InnoDB; 


-- ----------------------------------------------------- 
-- Table `mydb`.`cadastro_fornecedor` 
-- ----------------------------------------------------- 
CREATE TABLE IF NOT EXISTS `mydb`.`cadastro_fornecedor` (
    `id_cadastro` INT NOT NULL AUTO_INCREMENT, 
    `data` DATETIME NULL, 
    `id_administrador` INT NULL, 
    `CNPJ` VARCHAR(45) NULL, 
    PRIMARY KEY (`id_cadastro`), 
    INDEX `id_administrador_idx` (`id_administrador` ASC), 
    INDEX `CNPJ_idx` (`CNPJ` ASC), 
    CONSTRAINT `id_administrador` 
    FOREIGN KEY (`id_administrador`) 
    REFERENCES `mydb`.`administrador` (`id_administrador`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION, 
    CONSTRAINT `CNPJ` 
    FOREIGN KEY (`CNPJ`) 
    REFERENCES `mydb`.`fornecedores` (`CNPJ`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION) 
ENGINE = InnoDB; 


-- ----------------------------------------------------- 
-- Table `mydb`.`emprestimo` 
-- ----------------------------------------------------- 
CREATE TABLE IF NOT EXISTS `mydb`.`emprestimo` (
    `id_emprestimo` INT NOT NULL AUTO_INCREMENT, 
    `data_emprestimo` DATE NULL, 
    `data_devolucao_prevista` DATE NULL, 
    `matricula` INT NULL, 
    `id_administrador` INT NULL, 
    `codigo_exemplar` INT NULL, 
    PRIMARY KEY (`id_emprestimo`), 
    INDEX `matricula_idx` (`matricula` ASC), 
    INDEX `id_administrador_idx` (`id_administrador` ASC), 
    INDEX `codigo_exemplar_idx` (`codigo_exemplar` ASC), 
    CONSTRAINT `matricula` 
    FOREIGN KEY (`matricula`) 
    REFERENCES `mydb`.`usuario_cadastrado` (`matricula`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION, 
    CONSTRAINT `id_administrador` 
    FOREIGN KEY (`id_administrador`) 
    REFERENCES `mydb`.`administrador` (`id_administrador`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION, 
    CONSTRAINT `codigo_exemplar` 
    FOREIGN KEY (`codigo_exemplar`) 
    REFERENCES `mydb`.`exemplar` (`codigo_exemplar`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION) 
ENGINE = InnoDB; 


-- ----------------------------------------------------- 
-- Table `mydb`.`devolucao` 
-- ----------------------------------------------------- 
CREATE TABLE IF NOT EXISTS `mydb`.`devolucao` (
    `id_devolucao` INT NOT NULL, 
    `data_devolucao` DATE NULL, 
    `multa` INT NULL, 
    `matricula` INT NULL, 
    `id_administrador` INT NULL, 
    PRIMARY KEY (`id_devolucao`), 
    INDEX `matricula_idx` (`matricula` ASC), 
    INDEX `id_administrador_idx` (`id_administrador` ASC), 
    CONSTRAINT `matricula` 
    FOREIGN KEY (`matricula`) 
    REFERENCES `mydb`.`usuario_cadastrado` (`matricula`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION, 
    CONSTRAINT `id_administrador` 
    FOREIGN KEY (`id_administrador`) 
    REFERENCES `mydb`.`administrador` (`id_administrador`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION) 
ENGINE = InnoDB; 


-- ----------------------------------------------------- 
-- Table `mydb`.`exclusao` 
-- ----------------------------------------------------- 
CREATE TABLE IF NOT EXISTS `mydb`.`exclusao` (
    `id_exclusao` INT NOT NULL AUTO_INCREMENT, 
    `data_exclusao` DATE NULL, 
    `id_administrador` INT NULL, 
    `codigo_exemplar` INT NULL, 
    PRIMARY KEY (`id_exclusao`), 
    INDEX `id_administrador_idx` (`id_administrador` ASC), 
    INDEX `codigo_exemplar_idx` (`codigo_exemplar` ASC), 
    CONSTRAINT `id_administrador` 
    FOREIGN KEY (`id_administrador`) 
    REFERENCES `mydb`.`administrador` (`id_administrador`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION, 
    CONSTRAINT `codigo_exemplar` 
    FOREIGN KEY (`codigo_exemplar`) 
    REFERENCES `mydb`.`exemplar` (`codigo_exemplar`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION) 
ENGINE = InnoDB; 


-- ----------------------------------------------------- 
-- Table `mydb`.`registro` 
-- ----------------------------------------------------- 
CREATE TABLE IF NOT EXISTS `mydb`.`registro` (
    `id_registro` INT NOT NULL AUTO_INCREMENT, 
    `data_registro` DATE NULL, 
    `id_administrador` INT NULL, 
    `codigo_exemplar` INT NULL, 
    PRIMARY KEY (`id_registro`), 
    INDEX `id_administrador_idx` (`id_administrador` ASC), 
    INDEX `codigo_exemplar_idx` (`codigo_exemplar` ASC), 
    CONSTRAINT `id_administrador` 
    FOREIGN KEY (`id_administrador`) 
    REFERENCES `mydb`.`administrador` (`id_administrador`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION, 
    CONSTRAINT `codigo_exemplar` 
    FOREIGN KEY (`codigo_exemplar`) 
    REFERENCES `mydb`.`exemplar` (`codigo_exemplar`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION) 
ENGINE = InnoDB; 


-- ----------------------------------------------------- 
-- Table `mydb`.`reserva` 
-- ----------------------------------------------------- 
CREATE TABLE IF NOT EXISTS `mydb`.`reserva` (
    `id_reserva` INT NOT NULL, 
    `data_reserva` DATE NULL, 
    `matricula` INT NULL, 
    `ISBN` VARCHAR(20) NULL, 
    PRIMARY KEY (`id_reserva`), 
    INDEX `matricula_idx` (`matricula` ASC), 
    INDEX `ISBN_idx` (`ISBN` ASC), 
    CONSTRAINT `matricula` 
    FOREIGN KEY (`matricula`) 
    REFERENCES `mydb`.`usuario_cadastrado` (`matricula`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION, 
    CONSTRAINT `ISBN` 
    FOREIGN KEY (`ISBN`) 
    REFERENCES `mydb`.`obra` (`ISBN`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION) 
ENGINE = InnoDB; 


SET [email protected]_SQL_MODE; 
SET [email protected]_FOREIGN_KEY_CHECKS; 
SET [email protected]_UNIQUE_CHECKS;

내가 도움이 모든 종류의 감사 : 여기

는 .SQL입니다. 감사합니다. .

출처

2014-06-23 user3766086

가능한 중복 [MySQL의 오류 1022 때 생성 테이블 (http://stackoverflow.com/questions/15014592/mysql-error-1022-when-creating-table) –

오류 1022 중복이 있음을 나타냅니다 키 –

기존 제약 조건 이름을 다시 사용하고 있습니다. id_administrador는 이미 cadastro_usuario 테이블에서 제약 조건 이름으로 사용되고 CNPJ는 예제 테이블에서 사용됩니다. 제약 조건을 고유 한 이름으로 지정해야합니다 (여기에서 이름을 cf_id_administrador/CF_CNPJ);

-- ----------------------------------------------------- 
-- Table `mydb`.`cadastro_fornecedor` 
-- ----------------------------------------------------- 
CREATE TABLE IF NOT EXISTS `mydb`.`cadastro_fornecedor` (
    `id_cadastro` INT NOT NULL AUTO_INCREMENT, 
    `data` DATETIME NULL, 
    `id_administrador` INT NULL, 
    `CNPJ` VARCHAR(45) NULL, 
    PRIMARY KEY (`id_cadastro`), 
    INDEX `id_administrador_idx` (`id_administrador` ASC), 
    INDEX `CNPJ_idx` (`CNPJ` ASC), 
    CONSTRAINT `cf_id_administrador` 
    FOREIGN KEY (`id_administrador`) 
    REFERENCES `mydb`.`administrador` (`id_administrador`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION, 
    CONSTRAINT `CF_CNPJ` 
    FOREIGN KEY (`CNPJ`) 
    REFERENCES `mydb`.`fornecedores` (`CNPJ`) 
    ON DELETE NO ACTION 
    ON UPDATE NO ACTION) 
ENGINE = InnoDB;

의

출처

2014-06-23 04:45:38

MySQL WorkBench의 오류 코드 1022

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