사용자가 현재 암호를 입력했지만 올바르게 입력되었지만 더 이상 입력하지 않으면 오류 메시지가 나타나려고합니다. 그래서 예. 사용자는 자신의 비밀번호를 변경하고 현재 비밀번호를 입력하고 올바른 비밀번호를 입력하십시오. 'Please enter all fields!'라는 오류 메시지가 나타납니다. 제발 여기 http://gyazo.com/ea789cc87166cea88453d6c1c59733b6제출시 PHP 오류가 표시됩니다.
(이 말을해야 : 지금은 그냥 아무것도 난 정말 붙어있어 :(
어떤 도움이 좋을 것
IMAGE 1 :! http://gyazo.com/e58f10783bf14c79de487f4eeb05f7e8
이미지 2 모든 필드를 기입)
내 코드 :!
<title>Hondac</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<meta name="viewport" content="width=device-width, initial-scale=1, maximum-scale=1">
<link href='http://fonts.googleapis.com/css?family=Julius+Sans+One' rel='stylesheet' type='text/css'>
<link href="../css/style.css" rel="stylesheet" type="text/css" media="all" />
<?php
session_start();
$username = $_SESSION['sess_user'];
echo '<div class="search1"><h2>'.$username.'</h2><div class="search12"><h2><a href="index.php">Home</a></h2></p></div></div>';
if (isset($_SESSION['sess_user']))
{
//user is logged in
if (isset($_POST['submit']))
{
//start changing password
//check fields
$oldpassword = md5($_POST['oldpassword']);
$newpassword = md5($_POST['newpassword']);
$repeatnewpassword = md5($_POST['repeatnewpassword']);
//check password against db
include('../includes/config.php');
$queryget = mysql_query("SELECT password FROM login WHERE username='$username'") or die ("change password failed");
$row = mysql_fetch_assoc($queryget);
$oldpassworddb = $row['password'];
//check passwords
if ($oldpassword==$oldpassworddb && !empty($_POST['oldpassword']))
{
if (isset($_POST['repeatnewpassword']) AND isset($_POST['newpassword']) AND $_POST['newpassword'] != '') {
if ($newpassword==$repeatnewpassword)
{
$querychange = mysql_query("UPDATE login SET password='$newpassword' WHERE username='$username'");
echo "<div class='successmate'><br><br><br><br><hr>Password has been changed!</hr></div><div class='successmate'><br><hr><br><h2><p><a href='index.php'><br><br></a></p></h2></div>";
}
else {echo "<div class='results'>new password(s) dont match</div><div class='successmate'><br><br><h2><p><a href='changepassword.php'>try again?</a></p></h2></div>";}
}
}
else {echo "<div class='results'>current password doesnt match</div><div class='successmate'><h2><p><a href='changepassword.php'><br><br>Try again?</a></p></h2></div>";}
if (isset($_POST['email']) AND $_POST['email'] != '') {
$querychange = mysql_query("UPDATE login SET email='$email' WHERE username='$username'");
echo "<div class='successmate'><br><br><br><br><hr>Your email has been changed</hr></div><div class='successmate'><br><hr><br><h2><p><a href='index.php'><br><br></a></p></h2></div>";
}}
else
{
echo"
<form class='search1' action='changepassword.php' method='POST'>
<label>Current Password:*</label> <input type='password' id='password' name='oldpassword' required><p>
<label>New Password:*</label> <input type='password' id='password' name='newpassword'><p>
<label>Repeat New Password:*</label> <input type='password' name='repeatnewpassword'><p>
<input type='submit' name='submit' class='submit' value='submit'><br><br><br>
</form>
";
}}
else
die ("You must be logged in to change your password");
?>
<img src="../images/main.jpg">
HTML 코드를 출력 한 후 session_start()를 추가하지 마십시오. 오류가 발생합니다. – Qualcuno