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JMS 메시지가 대기열로 전달 된 후 Stream Closer와 관련된 log 문이 나타납니다. 그것은 나에게 보이지 않는다. 왜이 메시지를 보나요?Mule - 스트림 유형에 대한 StreamCloser를 찾을 수 없습니다. class java.lang.String
2013-04-22 19:08:29,385 [DEBUG] org.mule.transport.jms.activemq.ActiveMQJmsConnector - Returning dispatcher for endpoint: jms://retry.queue = EeJmsMessageDispatcher{this=5c5801d7, endpoint=jms://retry.queue, disposed=false}
2013-04-22 19:08:29,433 [DEBUG] org.mule.util.DefaultStreamCloserService - Unable to find an StreamCloser for the stream type: class java.lang.String, the stream: <?xml version="1.0" encoding="UTF-8"?> < ....... rest of the XML ....... /> will not be closed.
"스트림은 닫히지 않을 것입니다."
이 문제를 해결하려면 어떻게해야합니까?
==== 편집 :
오류가 발생했습니다. JMS 메시지에는 페이로드로 XML이 있습니다. 뮬 버전 : 3.3.2
여기 DEBUG
수준에서
<flow name="sendToHost">
<jms:inbound-endpoint queue="host.queue" exchange-pattern="one-way" />
<copy-properties propertyName="*" />
<file:outbound-endpoint path="/hostmessages" outputPattern="outgoing-xml-[function:dateStamp].log" />
<set-variable variableName="hostXML" value="#[payload]" />
<flow-ref name="webServiceCall" />
<flow-ref name="inspectWSResponse" />
<exception-strategy ref="retryExceptionStrategy" />
</flow>
<flow name="resendFailedMessages">
<description>
"*/15 07-18 * * ?" run every 15 minutes from 7 am to 6 pm every day -->
</description>
<quartz:inbound-endpoint jobName="hostRedeliveryJob" cronExpression="0 0/1 * * * ?">
<quartz:endpoint-polling-job>
<quartz:job-endpoint ref="redeliverToHost" />
</quartz:endpoint-polling-job>
</quartz:inbound-endpoint>
<set-variable variableName="hostXML" value="#[payload]" />
<logger message="QUARTZ found message for host" level="INFO" />
<flow-ref name="webServiceCall" />
<flow-ref name="inspectWSResponse" />
<exception-strategy ref="retryExceptionStrategy" />
</flow>
<choice-exception-strategy name="retryExceptionStrategy">
<catch-exception-strategy when="#[exception.causedBy(java.io.IOException)]">
<logger message="In retryExceptionStrategy IO exception strategy. " level="ERROR" />
<logger message="retryExceptionStrategy exception is #[exception.causeException]" level="ERROR" />
<set-property propertyName="exception" value="#[exception.summaryMessage]" />
<set-payload value="#[hostXML]" />
<logger message="retryExceptionStrategy payload is #[payload]" level="ERROR" />
<jms:outbound-endpoint queue="retry.queue" />
</catch-exception-strategy>
<catch-exception-strategy>
<logger message="Other error in sending result to host in retryExceptionStrategy flow." level="INFO" />
<set-property propertyName="exception" value="#[exception.summaryMessage]" />
<set-payload value="#[hostXML]" />
<jms:outbound-endpoint queue="declined.queue" />
</catch-exception-strategy>
</choice-exception-strategy>
<sub-flow name="webServiceCall">
<cxf:proxy-client payload="body" enableMuleSoapHeaders="false">
<cxf:inInterceptors>
<spring:bean class="org.apache.cxf.interceptor.LoggingInInterceptor" />
</cxf:inInterceptors>
<cxf:outInterceptors>
<spring:bean class="org.apache.cxf.interceptor.LoggingOutInterceptor" />
</cxf:outInterceptors>
</cxf:proxy-client>
<outbound-endpoint address="${host.ws.url}" mimeType="text/xml" connector-ref="http.connector" />
<byte-array-to-string-transformer />
</sub-flow>
<sub-flow name="inspectWSResponse">
<choice>
<when expression="#[xpath('//acord:TestResult/acord:TestCode/acord:Name/@tc').value == '1']">
<logger message="Message Delivered Successfully to host" level="INFO" />
</when>
<otherwise>
<set-payload value="#[hostXML]" />
<jms:outbound-endpoint queue="declined.queue" />
</otherwise>
</choice>
</sub-flow>
David ... 그것을 보아 주셔서 감사합니다. 나는 그 질문을 갱신했다. – user1493140
나는 이것이 (당신이 지정하지 않은)'javax.jmx.TextMessage '라고 가정한다. 오류가 있기 때문에,이'DEBUG' 메시지가 예상됩니다. 그에 따라 내 대답을 업데이 트되었습니다. –