낙타 프로세서에서 스프링 빈을 autowiring

Question

Jboss Fuse 6.1 컨테이너에서 실행하기 위해 OSGI 번들을 구축 중입니다. 프로젝트는 blueprint.xml (src/main/resoureces/OSGI-INF/blueprint에 있음)을 포함합니다. 콘텐츠 :

<blueprint xmlns="http://www.osgi.org/xmlns/blueprint/v1.0.0" 
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
       xmlns:camel="http://camel.apache.org/schema/blueprint" 
       xmlns:camelcxf="http://camel.apache.org/schema/blueprint/cxf" 
       xmlns:cxf="http://cxf.apache.org/blueprint/core" 
       xmlns:jaxws="http://cxf.apache.org/blueprint/jaxws" 

       xsi:schemaLocation=" 
      http://www.osgi.org/xmlns/blueprint/v1.0.0 http://www.osgi.org/xmlns/blueprint/v1.0.0/blueprint.xsd 
      http://camel.apache.org/schema/blueprint/cxf http://camel.apache.org/schema/blueprint/cxf/camel-cxf.xsd 
      http://camel.apache.org/schema/blueprint http://camel.apache.org/schema/blueprint/camel-blueprint.xsd 
      http://cxf.apache.org/blueprint/jaxws http://cxf.apache.org/schemas/blueprint/jaxws.xsd 
    http://cxf.apache.org/blueprint/core http://cxf.apache.org/schemas/blueprint/core.xsd" 
    > 
<bean id="MyProcessor" class="com.test.MyProcessor" /> 
      <camelContext trace="false" id="blueprintContext" xmlns="http://camel.apache.org/schema/blueprint"> 
      <route> 
       <from uri="activemq:queue:paymentsqueue?username=admin&amp;password=admin" id="NotificationRoute"> 
        <description/> 
       </from> 
       <log message="The message contains ${body}"/> 
       <process ref="MyProcessor"/> 
      </route> 
     </camelContext> 
    </blueprint> 

내 목표는 MyProcessor에서 스프링 빈을 사용하고 있습니다. 이 MyProcessor에 대한 코드입니다 :

public class MyProcessor implements Processor { 

@Aurowired 
private Sender sender; 

@Override 
public void process(Exchange x) throws Exception { 
    log.info("test: " +sender.getSenderId()); 
} 

}

를하지만 나에게 NullPointerException이 있습니다. 내가 뭘 잘못하고 있니?

이 내 스프링 구성 파일의 내용입니다

<beans xmlns="http://www.springframework.org/schema/beans" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:context="http://www.springframework.org/schema/context" 
    xmlns:p="http://www.springframework.org/schema/p" 
    xmlns:aop="http://www.springframework.org/schema/aop" 
    xmlns:tx="http://www.springframework.org/schema/tx" 
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd 
    http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.1.xsd 
    http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.1.xsd 
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.1.xsd"> 
    <context:annotation-config/> 
    <context:component-scan base-package="com.username"/> 
<bean id="sender" class="com.username.Sender" scope="prototype"> 
    <property name="senderId" value="sendername" /> 
    <property name="password" value="senderpassword" /> 
</bean> 

Answer 1

난 당신이 프로세서 MyProcessor로 선언하지 않은 생각 (전/주/resoureces/META-INF/봄 SRC에 배치)

<bean id="myProcessor" 
     class="com.test.MyProcessor" /> 

같은 봄에 콩 당신은

<process ref="myProcessor"/> 

로 사용할 수 있습니다

또한

@Aurowired 
private Sender sender; 

(이 오타되어야하지만 지적.) @Autowired한다