MS SQL 서버 2014 : 나는 다음과 같은 구조 (발생 표)이있는 테이블이

Question

발생 수 사이의 일 수를 가져옵니다 :

ID EmployeeID  DateOfOccurrence 
-------------------------------------- 
1  999999   2017-02-14 
2  999999   2017-03-02 
3  999999   2017-03-23 
4  999999   2017-05-10 

가 나는 결과를 반환하는 쿼리를 만들 싶습니다을 (직원 ID별로 그룹화) :

999999  2017-02-14 to 2017-03-02  16 days 
999999  2017-03-02 to 2017-03-23  21 days 
999999  2017-03-23 to 2017-05-10  48 days 
999999  2017-05-10 to <today>  xx days 

* <today> = current day (i.e., getdate()) 

미리 감사드립니다.

select 
    id 
    , range = concat(
     convert(char(10),dateofoccurence,120) 
    , ' to ' 
    , convert(char(10),isnull(lead(dateofoccurence) over (partition by employeeid order by dateofoccurence),getdate()),120) 
) 
    , days = concat(
     datediff(
     day 
     , dateofoccurence 
     , isnull(lead(dateofoccurence) over (partition by employeeid order by dateofoccurence),getdate()) 
    ) 
    , ' days') 
from t 

rextester 데모 : http://rextester.com/FNQ48539

반환 : concat(), lead(), isnull() 및 datediff() 사용

Answer 1

+----+--------------------------+---------+ 
| id |   range   | days | 
+----+--------------------------+---------+ 
| 1 | 2017-02-14 to 2017-03-02 | 16 days | 
| 2 | 2017-03-02 to 2017-03-23 | 21 days | 
| 3 | 2017-03-23 to 2017-05-10 | 48 days | 
| 4 | 2017-05-10 to 2017-05-24 | 14 days | 
+----+--------------------------+---------+