다음 쿼리는 모든 시간을 반환합니다 범위는 누군가가 영역 (vo.timegoout as empty_start
)을 떠나 때
지역은 비어 그 지역에 아무도 없다 (not exists (...)
). 누군가 입력하기 전까지는이 영역이 비어 있습니다 (min(vi.startentry) as empty_end
). 또한이 지역은 00:00:00
에서 첫 번째 방문자가 에터스 (union all select '00:00:00', (select min(startentry) from visits)
)까지 비어 있습니다.마지막 방문자가 나뭇잎 후 또한 비어 우리는이 결과를 얻을 것이다
| startentry | timegoout |
| 10:00:00 | 10:01:00 |
| 10:10:10 | 10:11:11 |
| 10:12:12 | 10:13:13 |
| 12:33:33 | 12:55:55 |
| 12:34:56 | 12:44:44 |
| 14:31:00 | 14:33:00 |
| 14:32:00 | 14:34:00 |
| 16:00:00 | 16:10:00 |
다음 샘플 데이터
을 감안할 때
23:59:59
(
union all select (select max(timegoout) from visits), '23:59:59'
)
까지 : 당신이 정확하려면
| empty_start | empty_end |
| 00:00:00 | 10:00:00 |
| 10:01:00 | 10:10:10 |
| 10:11:11 | 10:12:12 |
| 10:13:13 | 12:33:33 |
| 12:55:55 | 14:31:00 |
| 14:34:00 | 16:00:00 |
| 16:10:00 | 23:59:59 |
을 두 번째로 쿼리를 수정해야합니다.
select addtime(vo.timegoout, '00:00:01') as empty_start,
subtime(min(vi.startentry), '00:00:01') as empty_end
from visits vo -- leave area (visit out)
join visits vi -- enter area (visit in)
on vi.startentry > vo.timegoout
where not exists (
select *
from visits v
where v.timegoout > vo.timegoout
and v.startentry <= vo.timegoout
)
group by vo.timegoout
union all
select '00:00:00' as empty_start, (select subtime(min(startentry), '00:00:01') from visits) as empty_end from (select 1) dummy
having empty_start <= empty_end
union all
select (select addtime(max(timegoout), '00:00:01') from visits) as empty_start, '23:59:59' as empty_end from (select 1) dummy
having empty_start <= empty_end
order by empty_start
결과 :
| empty_start | empty_end |
| 00:00:00 | 09:59:59 |
| 10:01:01 | 10:10:09 |
| 10:11:12 | 10:12:11 |
| 10:13:14 | 12:33:32 |
| 12:55:56 | 14:30:59 |
| 14:34:01 | 15:59:59 |
| 16:10:01 | 23:59:59 |
가 처리 할 수있는 당신이 범위를 모두 포함하는 halper 테이블을 작성해야 5 분-범위 : 이제
| range_start | range_end |
| 00:00:00 | 00:04:59 |
| 00:05:00 | 00:09:59 |
...
| 23:50:00 | 23:54:59 |
| 23:55:00 | 23:59:59 |
다음 helper_5_minutes_ranges
테이블에
drop table if exists tmp_sequence;
create table tmp_sequence (seq mediumint unsigned null);
insert into tmp_sequence(seq)
values (null),(null),(null),(null),(null),(null),(null),(null),(null),(null);
insert into tmp_sequence(seq) select seq from tmp_sequence;
insert into tmp_sequence(seq) select seq from tmp_sequence;
insert into tmp_sequence(seq) select seq from tmp_sequence;
insert into tmp_sequence(seq) select seq from tmp_sequence;
insert into tmp_sequence(seq) select seq from tmp_sequence;
ALTER TABLE `tmp_sequence`
CHANGE COLUMN `seq` `seq` MEDIUMINT(8) UNSIGNED NOT NULL AUTO_INCREMENT FIRST,
ADD PRIMARY KEY (`seq`);
drop table if exists helper_5_minutes_ranges;
create table helper_5_minutes_ranges(
range_start time,
range_end time,
primary key (range_start, range_end)
);
insert into helper_5_minutes_ranges (range_start, range_end)
select sec_to_time((seq-1)*5*60) as range_start, sec_to_time((seq)*5*60-1) as range_end
from tmp_sequence ts
where ts.seq <= 288
;
drop table if exists tmp_sequence;
데이터 다음과 같은 질문을 할 수 있습니다. 아무도이 지역에 없었을 때 5 분 전체 범위를 선택하십시오.
결과 : 누군가가 지역
select r.*
from helper_5_minutes_ranges r
join visits v
on v.startentry <= r.range_end
and v.timegoout >= r.range_start
그리고 마침내이 괴물에왔다 때
| range_start | range_end |
| 00:00:00 | 00:04:59 |
...
| 10:05:00 | 10:09:59 |
| 10:15:00 | 10:19:59 |
...
| 12:25:00 | 12:29:59 |
| 13:00:00 | 13:04:59 |
...
| 14:25:00 | 14:29:59 |
| 14:35:00 | 14:39:59 |
...
| 15:55:00 | 15:59:59 |
| 16:15:00 | 16:19:59 |
...
| 23:55:00 | 23:59:59 |
이 예상 된 결과 같은 것을 반환하는 모든 5 분-범위를 선택
select r.*, 'visited' as type,
greatest(v.startentry, r.range_start) as vr_start,
least(v.timegoout, r.range_end) as vr_end
from helper_5_minutes_ranges r
join visits v
on v.startentry <= r.range_end
and v.timegoout >= r.range_start
union all
select mr.*, 'empty' as type,
greatest(er.empty_start, mr.range_start) as vr_start,
least(er.empty_end, mr.range_end) as vr_end
from (
select addtime(vo.timegoout, '00:00:01') as empty_start,
subtime(min(vi.startentry), '00:00:01') as empty_end
from visits vo -- leave area (visit out)
join visits vi -- enter area (visit in)
on vi.startentry > vo.timegoout
where not exists (
select *
from visits v
where v.timegoout > vo.timegoout
and v.startentry <= vo.timegoout
)
group by vo.timegoout
union all
select '00:00:00' as empty_start, (select subtime(min(startentry), '00:00:01') from visits) as empty_end from (select 1) dummy
having empty_start <= empty_end
union all
select (select addtime(max(timegoout), '00:00:01') from visits) as empty_start, '23:59:59' as empty_end from (select 1) dummy
having empty_start <= empty_end
) er
join helper_5_minutes_ranges mr
on mr.range_start <= er.empty_end
and mr.range_end >= er.empty_start
order by range_start, vr_start
결과 :
| range_start | range_end | type | vr_start | vr_end |
...
| 09:55:00 | 09:59:59 | empty | 09:55:00.000000 | 09:59:59.000000 |
| 10:00:00 | 10:04:59 | visited | 10:00:00.000000 | 10:01:00.000000 |
| 10:00:00 | 10:04:59 | empty | 10:01:01.000000 | 10:04:59.000000 |
| 10:05:00 | 10:09:59 | empty | 10:05:00.000000 | 10:09:59.000000 |
| 10:10:00 | 10:14:59 | empty | 10:10:00.000000 | 10:10:09.000000 |
| 10:10:00 | 10:14:59 | visited | 10:10:10.000000 | 10:11:11.000000 |
| 10:10:00 | 10:14:59 | empty | 10:11:12.000000 | 10:12:11.000000 |
| 10:10:00 | 10:14:59 | visited | 10:12:12.000000 | 10:13:13.000000 |
| 10:10:00 | 10:14:59 | empty | 10:13:14.000000 | 10:14:59.000000 |
...
2 가지 의견 : 범위 중 일부는 5 분 간격 이상을 다루고 데이터 세트에 주어진 범위가 표시되지 않으면 캘린더 테이블을 사용하여이 정보를 포함해야합니다. –
일반적으로 데이터 표시 문제는 프레젠테이션 계층/응용 프로그램 수준 코드 (사용 가능한 경우)에서 가장 효과적으로 해결됩니다 (간단한 PHP 루프 – Strawberry