sys argv의 Python 이스케이프 특수 문자

Question

sys.argv를 사용하는 스크립트가 있고 입력에 특수 문자 (세미콜론)가 포함될 수 있습니다.

def myscript(text) 
    print text 


a = myscript(sys.argv[1]) 
print a 

를 내가 시도 :

>> python script.py "With these words she greeted Prince Vasili Kuragin, a man of high rank and importance, who was the first to arrive at her reception. Anna Pavlovna had had a cough for some days. She was, as she said, suffering" from la grippe; grippe being then a new word in St. Petersburg"" 

내가 얻을 :

'With these words she greeted Prince Vasili Kuragin, a man of high rank and importance, who was the first to arrive at her reception. Anna Pavlovna had had a cough for some days. She was, as she said, suffering' 
None 
bash: grippe: command not found 

I를 내가 가진

.. 난 그냥 문자열로 입력이 필요하지만, 세미콜론은 모든 것을 망쳐 놨어요 그 안에 무엇이 들어 있는지에 관계없이 전체 문자열을 스크립트로 가져오고 싶습니다.

내가 시도 :

는 파이썬의 문제가 아니다

a = myscript(repr(sys.argv[1])) 
a = myscript(str(sys.argv[1])) 

Answer 1

, 당신은 호출 쉘에서 탈출해야합니다. 따옴표는 \"이고, 세미콜론은 \;입니다.

$ python testme.py "With these words she greeted Prince Vasili Kuragin, a man of high rank and importance, who was the first to arrive at her reception. Anna Pavlovna had had a cough for some days. She was, as she said, suffering\" from la grippe; grippe being then a new word in St. Petersburg\"" 

With these words she greeted Prince Vasili Kuragin, a man of high rank and importance, who was the first to arrive at her reception. Anna Pavlovna had had a cough for some days. She was, as she said, suffering" from la grippe; grippe being then a new word in St. Petersburg" 

Answer 2

이, 그것은 bash는 문제 파이썬 문제입니다하지 않습니다. Bash는 ; (세미콜론)이 새로운 bash 명령을 분리한다고 생각합니다. 당신은 그것을 벗어날 필요가 있습니다.