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cakephp 및 mysql을 사용하여 저장 프로 시저에 문자열을 전달해야합니다. 열 수 없습니다 : 여기 열을 찾을 수 없습니다 : 1054 알 수없는 'Fielding list'의 'PlantingBlock.id'열
이 오류를 제공SET whereClause = " AND 1 = 1 ";
IF(in_clause IS NULL OR in_clause = '') THEN
SET whereClause = CONCAT(whereClause, ' AND ',in_clause);
END IF;
SET statement = 'SELECT PlantingBlock.* FROM (
SELECT PB.*,
B.block,
V.variety,
ST.size_type,
PLA.date AS plant_date,
PLA.week_no,
C.crop,
C.id AS crop_id
FROM lf_planting_blocks AS PB,
lf_blocks AS B,
lf_properties AS P,
lf_property_types AS PT,
lf_size_types AS ST,
lf_varieties AS V,
lf_plantings AS PLA,
lf_crops AS C
WHERE
PB.block_id = B.id
AND B.property_id = P.id
AND P.property_type_id = PT.id
AND B.size_type_id = ST.id
AND PB.variety_id = V.id
AND V.crop_id = C.id
AND PB.planting_id = PLA.id
AND PB.plant_still_active = true
AND B.is_deleted = false
AND P.is_deleted = false
AND PT.is_deleted = false
AND ST.is_deleted = false
AND V.is_deleted = false
AND C.is_deleted = false';
SET statement = CONCAT(statement, whereClause, ') AS PlantingBlock ORDER BY PlantingBlock.plant_date DESC');
내 저장 프로 시저,라고 내가 저장 프로 시저에 전달하고있어 문자열, 아래
PlantingBlock.id IN (13,10)
, SQLSTATE [42S22]입니다 발견 : 1054 '필드 목록'에 'PlantingBlock.id'알 수없는 열
@Irawana 당신이 (대답은, ** [동의] 도움 고려하시기 바랍니다 것처럼 느끼는 경우 http://meta.stackexchange.com/questions/5234/how-does-accepting-an-answer- 작동시켜. – peterm