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지난 며칠간 안드로이드에 멀티 파트 양식을 게시하려고했지만 문자열 데이터와 파일을 모두 보낼 수 없습니다. 내 파일을 업로드하려면 다음 코드를 사용하고 있고 그것은 잘 작동합니다. 그러나 내 요청에 문자열 데이터를 추가 할 때 부족합니다.Android에서 파일과 함께 게시물 데이터를 보내는 방법은 무엇입니까?
요청에 profile_id=1234&text=HERE IS MY TEXT&global=0
을 추가해야한다고 상상해보십시오. 어떻게해야합니까?
String fileName = photoPath;
HttpURLConnection conn = null;
DataOutputStream dos = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
try {
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(new File(photoPath));
URL url = new URL(Util.URL_POST_FEED);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("file", fileName);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"file\";filename=\""
+ fileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
int serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : "
+ serverResponseMessage + ": " + serverResponseCode);
if (serverResponseCode == 200) {
runOnUiThread(new Runnable() {
public void run() {
Toast.makeText(c, "File Upload Complete.",
Toast.LENGTH_SHORT).show();
}
});
}
InputStream stream = conn.getInputStream();
InputStreamReader isReader = new InputStreamReader(stream);
//put output stream into a string
BufferedReader br = new BufferedReader(isReader);
Log.d("Read", br.readLine());
//close the streams //
fileInputStream.close();
dos.flush();
dos.close();
} catch (MalformedURLException ex) {
ex.printStackTrace();
runOnUiThread(new Runnable() {
public void run() {
Toast.makeText(c, "MalformedURLException",
Toast.LENGTH_SHORT).show();
}
});
Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
} catch (Exception e) {
e.printStackTrace();
runOnUiThread(new Runnable() {
public void run() {
Toast.makeText(c, "Got Exception : see logcat ",
Toast.LENGTH_SHORT).show();
}
});
Log.e("Upload file to server Exception", "Exception : "
+ e.getMessage(), e);
}
확인하십시오. http://www.codejava.net/java-se/networking/upload-files-by-sending-multipart-request-programmatically –
@JaiSoni 감사합니다. 완벽하게 작동했습니다. 내 대답을 들어 주시면 받아 들일 수 있을까요? –
가능한 [jsp 응용 프로그램에서 다운로드를 얻기 위해 java를 사용하여 HTML 양식 데이터 제출] (http://stackoverflow.com/questions/18153691/submit-html-form-data-using-java-to-retrive-a) -download-from-a-jsp-application) – Mogsdad