전자 메일로 인코딩 된 첨부 파일을 수신하는 Java 정규식 문자열

Question

전자 메일 MIME 메시지 문자열 (eml)에서 인코딩 된 단어 부분을 캐치하는 정규식을 작성하고 싶습니다. 예를 들어,이 이메일의 일부입니다

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나는 단지이 부분을 잡으려고 싶습니다

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나는 folowing 정규 표현식을 썼다 : (< = \ 연구 \ n \ 연구를 \ n) (. + \ r \ n) + (? = -) 내가 원하는 결과를 제공합니다. 그 가정합니다 : * 정규 표현식 이러한 부분의 모든 항목을 반환해야합니다. 원하는 부분 앞에 항상 공백 행이있는 복수의 *. * 원하는 부분 뒤에 항상 "-"가있는 줄 시작이옵니다 (줄 사이에 줄이있을 수 있음).

이 솔루션의 문제점은 입력 문자열이 길면 스레드 "main"java.lang.StackOverflowError에서 Exception을 얻는다는 것입니다. 왜 내가 정규식 효율성을 생각하게합니까? 정규 표현식을보다 정확하게 만들고 싶습니다. 우리는 원하는 부분 앞의 빈 줄 앞에 어딘가에 항상 "Content-Transfer-Encoding :"으로 시작하는 줄이 있다는 사실을 이용할 수 있습니다. 누군가 도와 드릴 수 있습니까?

Answer 1

스택 크기를 늘리려고 할 수 있습니다. -Xss2048k