2014-10-07 3 views
0

jquery와 stripe.js 플러그인을 사용하여 양식을 제출할 수 없습니다. 스트라이프 토큰을 만든 후 양식을 제출하고 싶습니다. Jquery 유효성 검사가 잘 작동하고 있습니다. 콘솔에 "객체가 함수가 아닙니다"라는 오류 메시지가 표시되면 토큰을 만들 수 있습니다.스트라이프 토큰을 작성한 후 양식을 제출하십시오.

<?php 
    if(count($_REQUEST)>4) 
    { 
     print_r($_REQUEST); 
     exit; 
    } 
    ?> 
    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" 
     "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> 
    <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> 

    <head> 
     <title>untitled</title> 
     <meta http-equiv="content-type" content="text/html;charset=utf-8" /> 
     <meta name="generator" content="Geany 0.21" /> 
    </head> 

    <body> 
     <script type="text/javascript" src="https://js.stripe.com/v2/"></script> 
      <script src="http://jqueryvalidation.org/files/lib/jquery.js"></script> 
     <script src="http://jqueryvalidation.org/files/dist/jquery.validate.js"></script> 

    <!-- ///////////////////////////////////////////////////////////////////////////////// --> 
     <!-- CONTACT FORM --> 
     <div class="col-lg-6"> 
     <h1>CONTACT</h1> 

      <h3 class="service_h3">Say Hello! Ask something?</h3>    

    <form class="cmxform" id="signupForm" method="post" action=""> 
      <fieldset> 
       <legend>Validating a complete form</legend> 
       <p> 
        <label for="firstname">Firstname</label> 
        <input id="firstname" name="firstname" type="text"> 
       </p> 
       <p> 
        <label for="lastname">Lastname</label> 
        <input id="lastname" name="lastname" type="text"> 
       </p> 
       <p> 
        <label for="username">Username</label> 
        <input id="username" name="username" type="text"> 
       </p> 


      <fieldset> 
       <div class="cardform"> 
       <span class="payment-errors"></span> 
       <div class="field"> 
       <label>Card Number</label> 
       <input type="text" size="20" autocomplete="off" class="input card-number" value="4242424242424242"> 
       </div>    
       <div class="field small"> 
        <label>CVC</label> 
        <input type="text" size="4" autocomplete="off" class="input card-cvc" value="424"> 
       </div> 
       <div class="field medium"> 
        <label>Expiration (MM/YYYY)</label> 
        <input type="text" class="input card-expiry-month" size="2" placeholder="MM" value="05"> 

        <input type="text" class="input card-expiry-year" size="4" placeholder="YYYY" value="2018"> 
       </div> 
       </div> 
       </fieldset> 

       <p> 
        <input class="btn" type="submit" name="submit" id="submit" value="Submit"/> 
       </p> 
      </fieldset> 
     </form> 
      </div> 
    </body> 

    </html> 
    <script> 


     Stripe.setPublishableKey("pk_test_q8JKhn0ydXmENnxCnJxxV7xC"); 

     function stripeResponseHandler(status, response) { 
      var $form = $('#signupForm'); 

      if (response.error) { 
      // Show the errors on the form 
      $form.find('.payment-errors').text(response.error.message); 
      $form.find('#submit').prop('disabled', false); 
      } else { 
      // response contains id and card, which contains additional card details 
      var token = response.id; 
      // Insert the token into the form so it gets submitted to the server 
      $form.append($('<input type="hidden" name="stripeToken" />').val(token)); 
      // and submit 
      $form.get(0).submit(); 
      } 
     }; 

     $().ready(function() { 
     $("#signupForm").validate({ 
       rules: { 
        firstname: "required", 
        lastname: "required", 
        username: { 
         required: true, 
         minlength: 2 
        } 
       }, 
       messages: { 
        firstname: "Please enter your firstname", 
        lastname: "Please enter your lastname", 
        username: { 
         required: "Please enter a username", 
         minlength: "Your username must consist of at least 2 characters" 
        } 
      }, 
      submitHandler: function(form) { 

        Stripe.createToken({ 
         number: $('.card-number').val(), 
         cvc: $('.card-cvc').val(), 
         exp_month: $('.card-expiry-month').val(), 
         exp_year: $('.card-expiry-year').val() 
        }, stripeResponseHandler); 
        return false; // submit from callback 
       } 

      }); 

     }); 
     </script> 

답변

0

@ matthew-arkin이이 문제를 해결하는 데 도움이되었습니다. 그냥() 액션의 기본 .submit와 충돌 제출 button.its의 이름과 ID 속성을 제거

사용 :

<input class="btn" type="submit" value="Submit"/> 

대신 :

<input class="btn" type="submit" name="submit" id="submit" value="Submit"/> 
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