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PHP 언어로 ftp를 사용하여 mp3 파일을 서버에 업로드하려고합니다.이 코드에 대한 원시 코드 스크립트를 작성했습니다. 서버 이미지에서 pdf, doc 파일이 업로드되었지만 mp3 파일을 업로드 할 수 없습니다.ftp로 mp3 파일을 PHP로 서버에 업로드하려면 어떻게해야합니까?
Plz, 누구든지 나를 도울 까? 나는 심각한 문제에 빠져있다!
그것은, 내가 mp3 파일 여기
내 코드가 업로드하기 위하여려고 할 때 존재하지 않는 파일을 보여줍니다 -
<?php
// FTP Configuration
$FTP_User = $_POST["username"];
$FTP_Pass = $_POST["password"];
$FTP_Host = "###";
$FTP_Root = "$dir";
$action=$_GET["action"];
$username=$_POST["username"];
$password=$_POST["password"];
$dir=$_POST["dir"];
$Filename=$_POST["Filename"];
$MAX_FILE_SIZE= $_POST["MAX_FILE_SIZE"];
// If the form was submitted
if (isset($action) && $action == "submit") {
if ($_FILES['File_1']['size'] > $MAX_FILE_SIZE)
{
echo "Error: $Filename exceeds upload limit";
exit;
}
echo $_FILES['File_1']['size'];
echo $MAX_FILE_SIZE;
if ($dir == "-1")
{
echo "Error: Please choose a File Type to upload";
exit;
}
// Connect to the ftp address
$Connect = ftp_connect($FTP_Host);
if (!$Connect)
{
echo "Error: Could not connect to ftp server<br>";
exit;
}
echo "Connected to $FTP_Host<br>";
// Login
$login = ftp_login($Connect, $FTP_User, $FTP_Pass);
//Turns passive mode on
$passive = ftp_pasv ($Connect, true);
echo "Current directory is now: " . ftp_pwd($Connect) . "<br>";
if (ftp_chdir($Connect, "$FTP_Root"))
{
echo "Current directory is now: " . ftp_pwd($Connect) . "<br>";
} else echo "Cannot change directory";
$contents = ftp_nlist($Connect, ".");
// output $contents
print_r($contents);
// check upload status
if (!passive){
echo "Failed to enter passive mode.<br>";
}
else {
echo "Entered passive mode.<br>";
}
if (!$login)
{
echo "Error: Could not log on as $FTP_User<br>";
ftp_quit($Connect);
exit;
}
echo "Logged in as $FTP_User<br>";
// Set the filename to be uploaded
$Filename = $_FILES['File_1']['name'];
$myFile = $_FILES['File_1'];
//echo 'Filename is :'. $Filename;
print_r($myFile);
if (file_exists($Filename))
{
echo "The file $Filename exists<BR>";
}
else
{
echo "The file $Filename does not exist<BR>";
}
$destination_file = $FTP_ROOT.$_FILES['File_1']['name'];
// Set the local resource (the file that will be uploaded)
$file = $myFile['tmp_name'];
// If the file was successfully uploaded
$upload = ftp_put($Connect, $destination_file, $file, FTP_BINARY);
if (!$upload)
{
// Show success message
echo "There was a problem uploading $destination_file";
}
else
{
// Else show error message
echo "Successfully uploaded $Filename";
}
ftp_close($Connect);
}
?>
Form Code:
<html>
<head>
<title> PHP FTP Upload Test </title>
</head>
<body>
<table>
<form method="post" action="file_upload.php?action=submit" enctype="multipart/form-data">
<input type="hidden" name="MAX_FILE_SIZE" value="10000000">
<tr>
<td>Username:</td>
<td><input type="text" name="username" size="30"></td>
</tr>
<tr>
<td>Password:</td>
<td><input type="password" name="password" size="30"></td>
</tr>
<tr>
<td>File Type:</td>
<td><select name="dir">
<option value="-1">File Type</option>
<!--<option value="/httpdocs/charbel/upload/">Image</option>
<option value="/httpdocs/charbel/upload/">PDF</option>
<option value="/httpdocs/charbel/upload/">MP3</option>
<option value="/httpdocs/charbel/upload/">Video</option>
-->
<option value="/public_html/">Image</option>
<option value="/public_html/">PDF</option>
<option value="/public_html/">MP3</option>
<option value="/public_html/">Video</option>
</select>
</td>
</tr>
<tr>
<td>File:</td>
<td><input type="file" name="File_1" size="70"></td>
</tr>
<tr>
<td colspan="2" align="right"><input type="submit" value="Submit"></td>
</tr>
</form>
</table>
</body>
</html>
'$ MAX_FILE_SIZE = $ _POST [ "MAX_FILE_SIZE"];는 정말 안전하지 않습니다. – jantimon